To calculate the output voltage of the operational amplifier (op-amp) given the input voltages and parameters, follow these steps:

The output voltage \(V_{\text{out}}\) of an op-amp is given by the formula:

\(V_{\text{out}} = A_d \times V_d + A_c \times V_{\text{cm}}\)

where:

• \(A_d\) is the differential gain.
• \(V_d\) is the differential input voltage, calculated as \(V_{i1} - V_{i2}\).
• \(A_c\) is the common-mode gain.
• \(V_{\text{cm}}\) is the common-mode input voltage, calculated as the average of the two input voltages.

Given:

• Input voltages: \(V_{i1} = 150 \, \mu\text{V}\) and \(V_{i2} = 140 \, \mu\text{V}\)
• The differential gain \(A_d = 4000\)
• The Common-Mode Rejection Ratio (\text{CMRR}) is 100

Step 1: Calculate the differential input voltage, \(V_d\):

\(V_d = V_{i1} - V_{i2} = 150 \, \mu\text{V} - 140 \, \mu\text{V} = 10 \, \mu\text{V}\)

Step 2: Calculate the common-mode input voltage, \(V_{\text{cm}}\):

\(V_{\text{cm}} = \frac{V_{i1} + V_{i2}}{2} = \frac{150 \, \mu\text{V} + 140 \, \mu\text{V}}{2} = 145 \, \mu\text{V}\)

Step 3: Since \(CMRR = \frac{A_d}{A_c}\), the common-mode gain \(A_c = \frac{A_d}{\text{CMRR}}\). Thus,

\(A_c = \frac{4000}{100} = 40\)

Step 4: Calculate the output voltage \(V_{\text{out}}\):

\(V_{\text{out}} = A_d \times V_d + A_c \times V_{\text{cm}}\)

\(V_{\text{out}} = 4000 \times 10 \, \mu\text{V} + 40 \times 145 \, \mu\text{V}\)

\(V_{\text{out}} = 40000 \, \mu\text{V} + 5800 \, \mu\text{V}\)

\(V_{\text{out}} = 45800 \, \mu\text{V} = 45.8 \, \text{mV}\)

Thus, the output voltage is 45.8 mV.