For the sets $A=\{0, 1, 2, 3\}$, $B=\{2, 3\}$, $C=\{1, 2, 4\}$, Match List - I with List - II. Choose the correct answer from the options given below :List - I List - II A. $A - B$ I. $\{2\}$ B. $B \cap C$ II. $A$ C. $A \cup B$ III. $\{1, 2\}$ D. $A \cap C$ IV. $\{0, 1\}$
The problem requires matching set operations performed on given sets with their corresponding results.
Given sets:
The set difference $A - B$ contains elements that are in set $A$ but not in set $B$.
The result $\{0, 1\}$ corresponds to IV in List II.
The intersection $B \cap C$ contains elements that are common to both set $B$ and set $C$.
The result $\{2\}$ corresponds to I in List II.
The union $A \cup B$ contains all distinct elements from both set $A$ and set $B$.
The result $\{0, 1, 2, 3\}$ is the same as set $A$, which corresponds to II in List II.
The intersection $A \cap C$ contains elements that are common to both set $A$ and set $C$.
The result $\{1, 2\}$ corresponds to III in List III.
Based on the calculations:
Therefore, the correct matching is A-IV, B-I, C-II, D-III.
Match List - I with List - II.
| List - I | List - II | |
|---|---|---|
| A. Apple, Orange, Fruits | I. | |
| B. Son, Mother, Father | II. | ![]() |
| C. Cat, Dog, Elephant | III. | ![]() |
| D. Player, Cricket, Ground | IV. | ![]() |
Choose the correct answer from the options given below :
Match List - I with List - II : On the basis of share of expenditure in given pie chart.

| List - I | List - II |
| A. Percentage of Expenditure on Rent | I. $11.11$ |
| B. Percentage of Expenditure on Transport | II. $13.89$ |
| C. Percentage of Expenditure on Saving | III. $16.67$ |
| D. Percentage of Expenditure on Food | IV. $18.06$ |
Choose the correct answer from the options given below :