The efficiency of a rectifier is a measure of how effectively it converts AC power into DC power. The efficiency of a half-wave rectifier can be defined as the ratio of the DC power output to the AC power input.
The formula for the efficiency (\(\eta\)) of a half-wave rectifier is given by:
\[\eta = \frac{P_{\text{dc}}}{P_{\text{ac}}}\]For a half-wave rectifier, the efficiency is calculated as:
\[\eta = \frac{0.406 \times P_{\text{ac}}}{P_{\text{ac}}} = 0.406\]Converting this to percentage:
\[\eta = 40.60\%\]Therefore, the typical efficiency of a half-wave rectifier is 40.60%.
Let's evaluate the given options:
Thus, the correct answer is 40.60%, which corresponds to the efficiency of a half-wave rectifier.
For the series diode configuration of the given figure, determine $V_D$ and $I_D$.
For the given emitter-bias network, determine the values of $I_C$ and $V_{CE}$. Assume $\beta = 100$.
| List-I | List-II |
| Electronic Configuration | First Ionisation energy (kJ mol$^{-1}$) |
| (A). ns$^2$ | (I). 2100 |
| (B). ns$^2$np$^1$ | (II). 1400 |
| (C). ns$^2$np$^3$ | (III). 800 |
| (D). ns$^2$np$^6$ | (IV). 900 |
| List-I | List-II |
| Spectroscopy | Property |
| (A). Raman | (I). Polarizability |
| (B). FTIR | (II). Dipole Moment |
| (C). UV-Visible | (III). Absorbance |
| (D). NMR | (IV). Spin |