For the ANOVA table the F - statistics isSource of variations Sum of squares Degree of freedom Between treatment 75 3 Error 48 16 Total 123 19
8.33
The F-statistic is a key value in Analysis of Variance (ANOVA). It is used to test if there are significant differences between the means of three or more groups. To calculate the F-statistic from an ANOVA table, we need the Mean Square (MS) values for the 'Between treatment' source and the 'Error' source.
The provided ANOVA table is:
| Source of Variations | Sum of Squares | Degree of Freedom |
|---|---|---|
| Between treatment | 753 | 4 |
| Error | 4816 | 16 |
| Total | 12319 | 19 |
The F-statistic is the ratio of the Mean Square for 'Between treatment' to the Mean Square for 'Error'. The Mean Square for any source of variation is calculated by dividing its Sum of Squares (SS) by its corresponding Degrees of Freedom (df).
First, let's calculate the Mean Square for 'Between treatment':
\( MS_{Between} = \frac{SS_{Between}}{df_{Between}} \)
From the table, \( SS_{Between} = 753 \) and \( df_{Between} = 4 \).
\( MS_{Between} = \frac{753}{4} = 188.25 \)
Next, let's calculate the Mean Square for 'Error':
\( MS_{Error} = \frac{SS_{Error}}{df_{Error}} \)
From the table, \( SS_{Error} = 4816 \) and \( df_{Error} = 16 \).
\( MS_{Error} = \frac{4816}{16} = 301 \)
Now, we can calculate the F-statistic using the formula:
\( F = \frac{MS_{Between}}{MS_{Error}} \)
Substitute the calculated MS values:
\( F = \frac{188.25}{301} \approx 0.6254 \)
Based on the provided Sum of Squares and Degrees of Freedom in the ANOVA table, the calculated F-statistic is approximately \(0.6254\).
| Component | Description | How it's Calculated |
|---|---|---|
| Sum of Squares (SS) | Measures the total variability within a dataset or a source of variation. | Sum of squared differences from the mean. |
| Degrees of Freedom (df) | Represents the number of values in a calculation that are free to vary. | Depends on the number of groups and total number of observations. |
| Mean Square (MS) | An estimate of variance for a particular source of variation. | Sum of Squares divided by its Degrees of Freedom (MS = SS/df). |
| F-statistic | The ratio of the variance between groups to the variance within groups (error). | Mean Square Between divided by Mean Square Error (F = MSBetween / MSError). |
The F-test in ANOVA is used to determine if the observed differences in group means are statistically significant or likely due to random chance. A large F-statistic indicates that the variability between the group means is large relative to the variability within the groups. This suggests that at least one group mean is different from the others.
To make a decision about the statistical significance, the calculated F-statistic is compared to a critical F-value from the F-distribution table. The critical value depends on the degrees of freedom for the numerator (Between treatment) and the denominator (Error), as well as the chosen significance level (\(\alpha\), commonly 0.05).
If the calculated F-statistic is greater than the critical F-value, or if the p-value associated with the calculated F-statistic is less than \(\alpha\), the null hypothesis is rejected. The null hypothesis for a one-way ANOVA states that all group means are equal.
In a 3 races, 2 genders and 5 in each treatment group for two-way ANOVA, the degree of freedom for source of variation due to interaction, error and total respective are
The Pearson's correlation coefficient between following observation
| X: | 1 | 2 | 3 | 4 |
| Y: | 3 | 4 | 2 | 1 |
is -0.8. If each observation of X is halved and of Y is doubled, then Pearson's correlation coefficient equals to
For the ANOVA table
| Source of variations | Sum of squares | Degrees of freedom |
| Between treatment | 45 | 3 |
| Error | 32 | 16 |
| Total | 99 | 19 |
the F - statistics is:
For the ANOVA, which of the following options is INCORRECT?
In a two-way ANOVA table
| Source of Variation | Degree of Freedom | Sum of square | Mean sum of squares | F |
| Due to Level A | 2 | 294 | 147 | F A |
| Due to Level B | 2 | 6 | 3 | F B |
| Due to error | 4 | 12 | 3 | |
| Total | x | 312 |
the value of x, F A, F Bare: