The Pearson's correlation coefficient between following observation is -0.8. If each observation of X is halved and of Y is doubled, then Pearson's correlation coefficient equals toX: 1 2 3 4 Y: 3 4 2 1
-0.80
The question asks how the Pearson's correlation coefficient changes when the observations of the variables X and Y are transformed linearly. We are given the original correlation coefficient between X and Y is -0.8.
Pearson's correlation coefficient measures the strength and direction of a linear relationship between two variables. A key property of this coefficient is how it behaves under linear transformations.
Let's consider two variables X and Y with Pearson's correlation coefficient \(r_{XY}\). Suppose we transform these variables linearly to get new variables X' and Y':
\[ X' = aX + b \] \[ Y' = cY + d \]where a, b, c, and d are constants. The Pearson's correlation coefficient between the new variables X' and Y', denoted as \(r_{X'Y'}\), is related to the original correlation coefficient by the formula:
\[ r_{X'Y'} = \frac{ac}{|ac|} r_{XY} \]The term \(\frac{ac}{|ac|}\) is equal to 1 if the product of the scaling factors \(ac\) is positive, and -1 if \(ac\) is negative. This means:
The constant terms \(b\) and \(d\) (shifts in origin) do not affect the correlation coefficient.
In this specific problem, the original variables are X and Y, and their correlation is given as \(r_{XY} = -0.8\).
The new variables X' and Y' are obtained by:
Now, let's find the product of the scaling factors \(a\) and \(c\):
\[ ac = \left(\frac{1}{2}\right) \times (2) = 1 \]Since \(ac = 1\), which is positive (\(ac > 0\)), the factor \(\frac{ac}{|ac|}\) is:
\[ \frac{ac}{|ac|} = \frac{1}{|1|} = 1 \]Using the formula \(r_{X'Y'} = \frac{ac}{|ac|} r_{XY}\), we get:
\[ r_{X'Y'} = (1) \times r_{XY} \] \[ r_{X'Y'} = r_{XY} \]Since the original correlation coefficient \(r_{XY}\) is given as -0.8, the new Pearson's correlation coefficient \(r_{X'Y'}\) is:
\[ r_{X'Y'} = -0.8 \]When each observation of X is halved (scaled by a positive factor 1/2) and each observation of Y is doubled (scaled by a positive factor 2), the Pearson's correlation coefficient remains unchanged because both scaling factors are positive. The new correlation coefficient is therefore the same as the original one, which is -0.8.
| Original Observations | Transformed Observations |
|---|---|
| X: 1, 2, 3, 4 | X': 0.5, 1, 1.5, 2 |
| Y: 3, 4, 2, 1 | Y': 6, 8, 4, 2 |
| Original Correlation \(r_{XY}\) = -0.8 | New Correlation \(r_{X'Y'}\) = -0.8 |
The calculated new Pearson's correlation coefficient is -0.80, which corresponds to one of the given options.
| Transformation | Change in Correlation \(r_{X'Y'}\) | Condition |
|---|---|---|
| \(X' = aX + b, Y' = cY + d\) | \(r_{X'Y'} = r_{XY}\) | \(ac > 0\) (a and c same sign) |
| \(X' = aX + b, Y' = cY + d\) | \(r_{X'Y'} = -r_{XY}\) | \(ac < 0\) (a and c different signs) |
| \(X' = X + b, Y' = Y + d\) | \(r_{X'Y'} = r_{XY}\) | Pure shift (a=1, c=1, so ac=1 > 0) |
| \(X' = aX, Y' = cY\) | \(r_{X'Y'} = \frac{ac}{|ac|} r_{XY}\) | Scaling (b=0, d=0) |
The Pearson's correlation coefficient, often denoted by \(r\), is a standardized measure of the linear association between two continuous variables. It ranges from -1 to +1.
It is a dimensionless quantity, meaning it does not have the units of the variables being measured. This makes it useful for comparing the strength of relationships between different pairs of variables.
One of the properties that makes Pearson's r useful is its invariance under positive linear transformations. This means that if you change the scale or shift the origin of either variable (or both), the correlation coefficient will remain the same, provided the scaling factors are positive. If one or both scaling factors are negative, the sign of the correlation changes, reflecting a reversal in the direction of the relationship.
For the ANOVA table
| Source of variations | Sum of squares | Degree of freedom |
| Between treatment | 75 | 3 |
| Error | 48 | 16 |
| Total | 123 | 19 |
the F - statistics is
In a 3 races, 2 genders and 5 in each treatment group for two-way ANOVA, the degree of freedom for source of variation due to interaction, error and total respective are
For the ANOVA table
| Source of variations | Sum of squares | Degrees of freedom |
| Between treatment | 45 | 3 |
| Error | 32 | 16 |
| Total | 99 | 19 |
the F - statistics is:
For the ANOVA, which of the following options is INCORRECT?
In a two-way ANOVA table
| Source of Variation | Degree of Freedom | Sum of square | Mean sum of squares | F |
| Due to Level A | 2 | 294 | 147 | F A |
| Due to Level B | 2 | 6 | 3 | F B |
| Due to error | 4 | 12 | 3 | |
| Total | x | 312 |
the value of x, F A, F Bare: