$\frac{32}{46} \times \frac{94}{576} \times \frac{184}{282}$
Calculate the value of the expression:
$ \frac{32}{46} \times \frac{94}{576} \times \frac{184}{282} $
Simplify by canceling common factors between numerators and denominators.
Simplify individual fractions by dividing by common factors:
The expression becomes:
$ \frac{16}{23} \times \frac{47}{288} \times \frac{92}{141} $
Identify factors for cross-cancellation:
Substitute these into the expression:
$ \frac{16}{23} \times \frac{47}{16 \times 18} \times \frac{23 \times 4}{47 \times 3} $
Cancel the common factors ($16$, $23$, $47$) from numerators and denominators:
$ \frac{\cancel{16}}{\cancel{23}} \times \frac{\cancel{47}}{\cancel{16} \times 18} \times \frac{\cancel{23} \times 4}{\cancel{47} \times 3} $
This leaves:
$ \frac{1}{1} \times \frac{1}{18} \times \frac{4}{3} $
Multiply the remaining terms:
$ \frac{1 \times 1 \times 4}{1 \times 18 \times 3} = \frac{4}{54} $
Simplify the final fraction by dividing the numerator and denominator by 2:
$ \frac{4}{54} = \frac{2}{27} $
The value of the expression is $ \frac{2}{27} $.
What is the value of
$\frac{7}{9} - \frac{11}{12} + \frac{13}{16} - \frac{1}{8}$?
5 \(\frac{3}{4}\) + x + 2 \(\frac{1}{2}\) = 10 \(\frac{1}{8}\) Find the value of x.
Simplify the expression 441 ÷ \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)
Number 0.232323 can be written in rational form as:
Solve: \(\frac{1}{2}\) [{-2(2 + 3)*20}/2]
Match the following.
Column I | Column II | ||
a. | Equivalent fraction of \(\frac{7}{12}\) is | i. | Proper fraction |
b. | Equivalent fraction of \(\frac{9}{15}\) is | ii. | Improper fraction |
c. | \(\frac{7}{11}\) is | iii. | \(\frac{21}{36}\) |
d. | \(\frac{19}{5}\) is | iv. | \(\frac{3}{5}\) |