$\frac{32}{46} \times \frac{94}{576} \times \frac{184}{282}$
Calculate the value of the expression:
$ \frac{32}{46} \times \frac{94}{576} \times \frac{184}{282} $
Simplify by canceling common factors between numerators and denominators.
Simplify individual fractions by dividing by common factors:
The expression becomes:
$ \frac{16}{23} \times \frac{47}{288} \times \frac{92}{141} $
Identify factors for cross-cancellation:
Substitute these into the expression:
$ \frac{16}{23} \times \frac{47}{16 \times 18} \times \frac{23 \times 4}{47 \times 3} $
Cancel the common factors ($16$, $23$, $47$) from numerators and denominators:
$ \frac{\cancel{16}}{\cancel{23}} \times \frac{\cancel{47}}{\cancel{16} \times 18} \times \frac{\cancel{23} \times 4}{\cancel{47} \times 3} $
This leaves:
$ \frac{1}{1} \times \frac{1}{18} \times \frac{4}{3} $
Multiply the remaining terms:
$ \frac{1 \times 1 \times 4}{1 \times 18 \times 3} = \frac{4}{54} $
Simplify the final fraction by dividing the numerator and denominator by 2:
$ \frac{4}{54} = \frac{2}{27} $
The value of the expression is $ \frac{2}{27} $.
Which fraction among the following is the least ?
\(\frac{5}{11}, \frac{7}{12}, \frac{8}{13}, \frac{9}{17}\)
Find the value of the following expression:
\(\frac{{3 \div 1 \times 2 + 5 - 2}}{{3 \times 3 - 2}}\)
Simplify the expression 441 ÷ \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)
If the sum of two positive numbers is 65 and the square root of their product is 26, then the sum of their reciprocals is:
The value of \(9 \div [\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{6}\div(\frac{3}{4}-\frac{1}{3})\;of\;\frac{2}{9}]\) is: