All Exams Test series for 1 year @ ₹349 only
Question

By how much does $\frac{12}{\left(\frac{13}{14}\right)}$ exceed $\frac{\left(\frac{12}{13}\right)}{14}$?

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
$12\frac{6}{7}$

Solving Fraction Exceedance Problem

This problem requires us to calculate the difference between two fractional expressions. We need to evaluate each expression individually and then find out by how much the first value is greater than the second.

Step 1: Evaluate the First Expression

The first expression given is $\frac{12}{\left(\frac{13}{14}\right)}$.

To simplify this, we can multiply the numerator by the reciprocal of the denominator:

$ \frac{12}{\left(\frac{13}{14}\right)} = 12 \times \frac{14}{13} $

Performing the multiplication:

$ \frac{12 \times 14}{13} = \frac{168}{13} $

Step 2: Evaluate the Second Expression

The second expression is $\frac{\left(\frac{12}{13}\right)}{14}$.

This can be rewritten as:

$ \frac{12}{13} \div 14 = \frac{12}{13} \times \frac{1}{14} $

Multiplying these fractions gives:

$ \frac{12 \times 1}{13 \times 14} = \frac{12}{182} $

Simplify this fraction by dividing both the numerator and denominator by their greatest common divisor, which is 2:

$ \frac{12 \div 2}{182 \div 2} = \frac{6}{91} $

Step 3: Calculate the Difference (Exceedance)

We need to find the amount by which $\frac{168}{13}$ exceeds $\frac{6}{91}$. This is done by subtraction:

$ \frac{168}{13} - \frac{6}{91} $

To subtract these fractions, find a common denominator. The least common multiple (LCM) of 13 and 91 is 91, because $13 \times 7 = 91$.

Convert $\frac{168}{13}$ into an equivalent fraction with the denominator 91:

$ \frac{168}{13} = \frac{168 \times 7}{13 \times 7} = \frac{1176}{91} $

Now, perform the subtraction:

$ \frac{1176}{91} - \frac{6}{91} = \frac{1176 - 6}{91} = \frac{1170}{91} $

Step 4: Convert to a Mixed Number

The result $\frac{1170}{91}$ is an improper fraction. Convert it into a mixed number.

Divide 1170 by 91:

$ 1170 \div 91 = 12 \text{ with a remainder of } 78 $

This gives the mixed number $12\frac{78}{91}$.

Step 5: Simplify the Fractional Part

The fractional part of the mixed number, $\frac{78}{91}$, can be simplified. Find the greatest common divisor (GCD) of 78 and 91, which is 13.

Divide both the numerator and the denominator by 13:

$ \frac{78 \div 13}{91 \div 13} = \frac{6}{7} $

So, the final simplified answer is $12\frac{6}{7}$.

Was this answer helpful?

Similar Questions

  1. $1.236576576...$
    can be written in the form of:
  2. What is the sum of $\frac{1}{3}$, $\frac{4}{3}$ and $\frac{3}{4}$?
  3. Four persons A, B, C and D completed a task in $\frac{2}{3} \text{ h}, \frac{3}{4} \text{ h}, \frac{4}{5} \text{ h}$ and $\frac{1}{5} \text{ h}$ respectively. Who among the following took the highest amount of time to complete the task?
  4. The value of $\frac{4}{3} + \left( \frac{1}{1 + \frac{5}{6}} \right) - \frac{5}{4}$ is
  5. What is the value of 

    $\frac{7}{9} - \frac{11}{12} + \frac{13}{16} - \frac{1}{8}$?

  6. How much does one need to add to $\frac{1}{2}$ to get $2$?
  7. The sum of the numerator and denominator of a fraction is 11. If the numerator is decreased by 1, the fraction becomes $\frac{1}{4}$. Find the fraction.
  8. If the numerator of a fraction is increased by 30% and its denominator is decreased by 35%, the value of the fraction becomes $\frac{3}{15}$. Find the original fraction.
  9. Two-fifth of seven-seventeenth of three-fifth of a number is 84. Find 40% of that number.
  10. A beautician's income includes her salary and the tips she gets for her services. During a particular week, if her tips were $\frac{5}{4}$ of her salary, then what fraction of her income came from the tips?

Important Questions from Fractions

  1. 5 \(\frac{3}{4}\) + x + 2  \(\frac{1}{2}\) = 10  \(\frac{1}{8}\) Find the value of x.

  2. Simplify the expression 441 ÷  \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)

  3. Number 0.232323 can be written in rational form as:

  4. Solve: \(\frac{1}{2}\)  [{-2(2 + 3)*20}/2]

  5. Match the following.

    Column I

    Column II

    a.

    Equivalent fraction of \(\frac{7}{12}\)  is  

    i.

    Proper fraction

    b.

    Equivalent fraction of  \(\frac{9}{15}\)  is

    ii.

    Improper fraction

    c.

    \(\frac{7}{11}\)  is

    iii.

    \(\frac{21}{36}\)

    d.

    \(\frac{19}{5}\)  is

    iv.

    \(\frac{3}{5}\)

Need Expert Advice?
Upcoming Exams
RRB Technician
October 06, 2026
RRB JE
October 27, 2026
RRB ALP
November 03, 2026
Test Series
RRB NTPC img
Railways
RRB NTPC Under Graduate 2026 New Mock Test Series
1580 Tests 2 Tests Free
542 Attempts
4.3(498)
English, Hindi, Telugu +7 More

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App