The first step is to determine the annual interest rate (R) using the given information for yearly compounding.
We use the compound interest formula: $A = P \times (1 + \frac{R}{100})^t$.
$18515 = 14000 \times (1 + \frac{R}{100})^2$
$(1 + \frac{R}{100})^2 = \frac{18515}{14000}$
$(1 + \frac{R}{100})^2 = 1.3225$
Taking the square root on both sides:
$1 + \frac{R}{100} = \sqrt{1.3225}$
$1 + \frac{R}{100} = 1.15$
$\frac{R}{100} = 1.15 - 1$
$\frac{R}{100} = 0.15$
$R = 15\%$ per annum.
Next, we calculate the compound interest for the same principal (P = ₹ 14000) and rate (R = 15% p.a.) over 2 years, but with 8-monthly compounding.
Calculate the number of compounding periods in 2 years:
Number of periods = Time in years $\times$ (12 months / Period in months)
Number of periods (n) = $2 \times (\frac{12}{8}) = 2 \times 1.5 = 3$.
Calculate the interest rate per period:
Rate per period = $\frac{\text{Annual Rate}}{\text{Number of periods per year}} = \frac{15\%}{1.5} = 10\%$.
Now, calculate the amount (A2) using the compound interest formula with these adjusted values:
$A2 = P \times (1 + \frac{\text{Rate per period}}{100})^n$
$A2 = 14000 \times (1 + \frac{10}{100})^3$
$A2 = 14000 \times (1.1)^3$
$A2 = 14000 \times 1.331$
$A2 = 18634$
The compound interest (CI) is the difference between the final amount (A2) and the principal (P).
$CI = A2 - P$
$CI = 18634 - 14000$
$CI = ₹ 4634$
Find the interest (in ₹) on ₹8,000 at 10% per annum compounded half yearly for $1\frac{1}{2}$ years.
The difference between the simple interest and the compound interest, compounded annually, on a certain sum of money for 2 years at 17% per annum is ₹967. Find the sum [rounded off to the nearest integer].