A solid cylinder has a base of radius 14 cm and height 15 cm. 4 identical cylinders are cut from each base as shown in the given figure. Height of small cylinder is 5 cm. What is the total surface area (in cm 2) of the remaining part?
3432
Radius of larger cylinder = 14 cm and height = 15 cm
Radius of smaller cylinders = 28/8 = 7/2 cm and height = 5 cm
When the cylinders are cut as given in the question, the curved surface area of the
Remaining part will increase and CSA of the smaller cylinders will add up. While base area Will decrease by area of one base and increase by area of another base of the smaller
Cylinders thus no increment in base area.
CSA of the remaining part = 2πrh + 8 × 2πr 1h 1 (∵ There are two bases(top + base) in a cylinder and according to question, 4 small cylinders are cut out from each base ∴ we multiplied it by 8)
⇒ 2 × 22/7 (14 × 15 + 8 × 5 × 7/2)
⇒ 2 × 22/7 × 350
⇒ 2200 cm 2
Total Base Area of remaining part = 2πr 2– 8πr 12 + 8πr 12
⇒ 2 × 22/7 × 196
⇒ 1232 cm 2
Total surface area of the remaining part = 2200 + 1232 = 3432 cm 2
Alternate Method
Diameter of small circle (D) is 2r.
So, AB = 4 × D = 4 × 2r = 8r = Diameter of large cylinder
So, 14 × 2 = 8r
⇒ r = 7/ 2 cm
Here
Total Surface Area = TSA
Curved Surface area = CSA
TSA = CSA of big cylinder + 8 ( CSA of small circle) + 8 (area of small circle) + 2 [area of big circle - 4 (area of small circle)]
TSA = 2πRH + 8 (2πrh)+(8πr 2) + 2 [πR 2 - 4πr 2]
= 2πRH + 16πrh + 8πr 2 +2πR 2- 8πr 2
= 2π [ RH + 8rh +R 2 ]
= 2π [14 × 15 + 8 × 7/ 2 × 5 + (14) 2]
= 28π [15 + 10 + 14]
= 28 × 22 /7 × 39 = 88 × 39
= 3432 cm 2
So the total surface area of the remaining part = 3432cm 2
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