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Question

A solid cylinder has a base of radius 14 cm and height 15 cm. 4 identical cylinders are cut from each base as shown in the given figure. Height of small cylinder is 5 cm. What is the total surface area (in cm 2) of the remaining part?

This question was previously asked in
SSC CGL 2017 (Tier 1) Previous Year Paper (16-Aug-2017) (Shift 1)
The correct answer is

3432

Radius of larger cylinder = 14 cm and height = 15 cm

Radius of smaller cylinders = 28/8 = 7/2 cm and height = 5 cm

When the cylinders are cut as given in the question, the curved surface area of the

Remaining part will increase and CSA of the smaller cylinders will add up. While base area Will decrease by area of one base and increase by area of another base of the smaller

Cylinders thus no increment in base area.

CSA of the remaining part = 2πrh + 8 × 2πr 1h 1 (∵ There are two bases(top + base) in a cylinder and according to question, 4 small cylinders are cut out from each base ∴ we multiplied it by 8)

⇒ 2 × 22/7 (14 × 15 + 8 × 5 × 7/2) 

⇒ 2 × 22/7 × 350

⇒ 2200 cm 2

Total Base Area of remaining part = 2πr 2– 8πr 12 + 8πr 12

⇒ 2 × 22/7 × 196

⇒ 1232 cm 2

Total surface area of the remaining part = 2200 + 1232 = 3432 cm 2

  Alternate Method

Let the radius of small cylinder be r.

Diameter of small circle (D) is 2r.

So, AB = 4 × D = 4 × 2r = 8r = Diameter of large cylinder 

So, 14  × 2 = 8r

⇒ r = 7/ 2 cm

Here

Total Surface Area = TSA

Curved Surface area = CSA

TSA = CSA of big cylinder + 8 ( CSA of small circle) + 8 (area of small circle) + 2 [area of big circle - 4 (area of small circle)]

TSA = 2πRH + 8 (2πrh)+(8πr 2) + 2 [πR 2 - 4πr 2]

= 2πRH + 16πrh  + 8πr 2 +2πR 2- 8πr 2

= 2π [ RH + 8rh +R 2 ] 

= 2π [14 × 15 + 8 × 7/ 2 × 5 + (14) 2]

= 28π [15 + 10 + 14]

= 28 × 22 /7  × 39 = 88 × 39

= 3432 cm 2

So the total surface area of the remaining part = 3432cm 2

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Similar Questions

  1. The curved surface area and the volume of a cylindrical object are 88 cm 2and 132 cm 3, respectively. The height (in cm) of the cylindrical object is:

    (Take π =   \(\frac{{22}}{7}\) )

  2. The circumference of the base of a cylindrical vessel is 264 cm and its height is 50 cm. The capacity (in litres) of the vessel is:

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  5. The volume of a right circular cone is 308 cm 3 and the radius of its base is 7 cm. What is the curved surface area (in cm 2) of the cone? (Take π =  \(\frac{22}{7} \) )

  6. The slant height and radius of a right circular cone are in the ratio 29 ∶ 20. If its volume is 4838.4 π cm 3, then its radius is: 

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Important Questions from Solid Figures

  1. A cone and a hemisphere have equal bases and volumes. What is the ratio of the height of the cone to the radius of the hemisphere?

  2. If the surface area of a sphere is 64 π cm 2, then the volume of the sphere is:

  3. Find the surface area of a sphere of diameter 21 cm. (Use π = \(\frac{{22}}{7}\) )

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