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Question

\(\rm \frac{\sin^4 \theta+\cos ^4\theta}{1-2\sin^2\theta.\cos^2\theta}=\) ________.

This question was previously asked in
SSC CGL 2023 (Tier-II) Paper 1 Previous Year Paper (26-Oct-2023) (Shift-1)
The correct answer is

1

Simplifying Trigonometric Expressions

This question asks us to simplify a given trigonometric expression involving powers of sine and cosine. To simplify, we will use fundamental trigonometric identities and algebraic manipulation.

Understanding the Expression

The expression we need to simplify is:

\(\rm \frac{\sin^4 \theta+\cos ^4\theta}{1-2\sin^2\theta.\cos^2\theta}\)

Let's look at the numerator and denominator separately.

Simplifying the Numerator: \(\sin^4 \theta+\cos ^4\theta\)

We can rewrite the numerator \(\sin^4 \theta+\cos ^4\theta\) using algebraic identities. Recall the identity \((a+b)^2 = a^2 + b^2 + 2ab\). From this, we can write \(a^2 + b^2 = (a+b)^2 - 2ab\).

Let \(a = \sin^2 \theta\) and \(b = \cos^2 \theta\).

Then, \(\sin^4 \theta+\cos ^4\theta = (\sin^2 \theta)^2 + (\cos^2 \theta)^2\).

Applying the identity \(a^2 + b^2 = (a+b)^2 - 2ab\), we get:

\(\sin^4 \theta+\cos ^4\theta = (\sin^2 \theta + \cos^2 \theta)^2 - 2(\sin^2 \theta)(\cos^2 \theta)\)

Now, we use the fundamental trigonometric identity: \(\sin^2 \theta + \cos^2 \theta = 1\).

Substitute this into the expression:

\(\sin^4 \theta+\cos ^4\theta = (1)^2 - 2\sin^2 \theta \cos^2 \theta\)

\(\sin^4 \theta+\cos ^4\theta = 1 - 2\sin^2 \theta \cos^2 \theta\)

So, the simplified form of the numerator is \(1 - 2\sin^2 \theta \cos^2 \theta\).

Analyzing the Denominator: \(1-2\sin^2\theta.\cos^2\theta\)

The denominator of the original expression is \(1-2\sin^2\theta.\cos^2\theta\). This is exactly the same as the simplified form of the numerator we found.

Putting it Together

Now substitute the simplified numerator back into the original expression:

\(\rm \frac{\sin^4 \theta+\cos ^4\theta}{1-2\sin^2\theta.\cos^2\theta} = \frac{1 - 2\sin^2 \theta \cos^2 \theta}{1 - 2\sin^2 \theta \cos^2 \theta}\)

Assuming the denominator is not zero (which is generally true for real \(\theta\) as explained below), the expression simplifies to:

\(\frac{1 - 2\sin^2 \theta \cos^2 \theta}{1 - 2\sin^2 \theta \cos^2 \theta} = 1\)

Condition for Denominator Not Being Zero

The denominator \(1-2\sin^2\theta.\cos^2\theta\) would be zero if \(1 = 2\sin^2\theta.\cos^2\theta\). We know that \(\sin(2\theta) = 2\sin\theta\cos\theta\), so \(\sin^2(2\theta) = 4\sin^2\theta\cos^2\theta\), which means \(\sin^2\theta\cos^2\theta = \frac{\sin^2(2\theta)}{4}\). Substituting this, we get \(1 = 2 \left(\frac{\sin^2(2\theta)}{4}\right) = \frac{\sin^2(2\theta)}{2}\). This means \(\sin^2(2\theta) = 2\). However, the maximum value of \(\sin^2\) of any angle is 1. Since \(\sin^2(2\theta)\) cannot be greater than 1, \(\sin^2(2\theta) = 2\) has no real solution for \(\theta\). Therefore, the denominator \(1-2\sin^2\theta.\cos^2\theta\) is never zero for real values of \(\theta\).

Conclusion

The simplified value of the expression \(\rm \frac{\sin^4 \theta+\cos ^4\theta}{1-2\sin^2\theta.\cos^2\theta}\) is 1.

Reviewing the Options

  • 1. 1
  • 2. 2
  • 3. -1
  • 4. 0

Our simplified value is 1, which matches option 1.

Step Expression Explanation
1 \(\sin^4 \theta+\cos ^4\theta\) Start with the numerator.
2 \((\sin^2 \theta)^2 + (\cos^2 \theta)^2\) Rewrite using squares.
3 \((\sin^2 \theta + \cos^2 \theta)^2 - 2\sin^2 \theta \cos^2 \theta\) Apply \(a^2+b^2 = (a+b)^2 - 2ab\) with \(a=\sin^2\theta, b=\cos^2\theta\).
4 \((1)^2 - 2\sin^2 \theta \cos^2 \theta\) Use \(\sin^2 \theta + \cos^2 \theta = 1\).
5 \(1 - 2\sin^2 \theta \cos^2 \theta\) Simplify the numerator.
6 \(\rm \frac{1 - 2\sin^2 \theta \cos^2 \theta}{1-2\sin^2\theta.\cos^2\theta}\) Substitute the simplified numerator into the original expression.
7 \(1\) Cancel the identical numerator and denominator.

Revision Table: Trigonometric Identities

Identity Description
\(\sin^2 \theta + \cos^2 \theta = 1\) The fundamental Pythagorean identity relating sine and cosine.
\(\sin(2\theta) = 2\sin\theta\cos\theta\) Double angle identity for sine. Useful for rewriting \(\sin\theta\cos\theta\).
\(a^2 + b^2 = (a+b)^2 - 2ab\) An algebraic identity useful for rewriting sums of squares.
\(a^4 + b^4 = (a^2+b^2)^2 - 2a^2b^2\) A specific application of the previous identity for fourth powers.

Additional Information: Simplifying Complex Trigonometric Expressions

Simplifying trigonometric expressions often involves recognizing patterns and applying fundamental identities. Here are some tips:

  • Look for opportunities to use the Pythagorean identity \(\sin^2 \theta + \cos^2 \theta = 1\).
  • Try to factor expressions or expand squares using algebraic identities.
  • Convert all terms to sine and cosine if possible, especially in expressions involving tan, cot, sec, or cosec.
  • Look for double angle or other compound angle identities if angles like \(2\theta\) or \(\theta/2\) appear.
  • If the expression involves powers like \(\sin^4 \theta\) or \(\cos^4 \theta\), think about how they relate to \(\sin^2 \theta\) and \(\cos^2 \theta\). The algebraic identity \(a^2+b^2=(a+b)^2-2ab\) is very useful here.
  • Always check if the denominator can be zero, although in many standard problems, it will be designed to be non-zero for real values of the variable.
  • Practice is key! Work through various examples to become comfortable with different techniques.

By applying these strategies, we can simplify complex trigonometric expressions effectively.

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Similar Questions

  1. If sin t + cos t = \(\frac{4}{5}\), then find sin t. cos t.

  2. If sec A + tan A = 5,then sin A is equal to:

  3. Simplify the given expression.

    \(\frac{1+sin^4 \theta+cos^4\theta}{cos^2 \theta+sin^4\theta}\)

  4. Which of the following will satisfy a2 = b2 + (ab)2 for the values a and b?

  5. If sec x – cos x = 4, then what will be the value of \({{(1 \ + \ cos^2 x)} \over cos x}\)?

  6. If cos θ + cos2θ =1, find the value of \(\sqrt{\sin^4θ + \cos^2θ}\).

  7. If Sin θ = \(\frac{4}{5}\), find the value of tan θ - Cot θ.

  8. In the given figure if AD ⊥ BC, AC = 26 units, CD = 10 units, BC = 42 units, ∠DAC = x and ∠B = y then the value of \(\rm \frac{6}{\cos x}-\frac{5}{\cos y}+8\tan y\) is:

  9. If a cot θ + b cosec θ = p and b cot θ + a cosec θ = q then p2 - q2 is equal to ______.

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Important Questions from Trigonometric Ratios and Identities

  1. What is the ratio of the greatest to the smallest value of 2 – 2 sin x – sin 2x, 0 ≤ x ≤ (π/2)? 

  2. If sinθ = \(\frac{4}{5}\) , Find the value of sin3θ

  3. If x, y are acute angles, where 0 < x + y < 90° and sin(3x - 40°) = cos (3y + 40°), then the value of tan (x + y) is equal to

  4. What is (1 + cot θ - cosec θ)(1 + tan θ + sec θ) equal to?

  5. If \(\sin \theta =\frac{3}{5}\)  and  \(\cos \theta =\frac{4}{5}\) , then the value of  \(\frac{1+\tan \theta}{1-\cot \theta}\)  is:

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