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This question asks us to simplify a given trigonometric expression involving powers of sine and cosine. To simplify, we will use fundamental trigonometric identities and algebraic manipulation.
The expression we need to simplify is:
\(\rm \frac{\sin^4 \theta+\cos ^4\theta}{1-2\sin^2\theta.\cos^2\theta}\)
Let's look at the numerator and denominator separately.
We can rewrite the numerator \(\sin^4 \theta+\cos ^4\theta\) using algebraic identities. Recall the identity \((a+b)^2 = a^2 + b^2 + 2ab\). From this, we can write \(a^2 + b^2 = (a+b)^2 - 2ab\).
Let \(a = \sin^2 \theta\) and \(b = \cos^2 \theta\).
Then, \(\sin^4 \theta+\cos ^4\theta = (\sin^2 \theta)^2 + (\cos^2 \theta)^2\).
Applying the identity \(a^2 + b^2 = (a+b)^2 - 2ab\), we get:
\(\sin^4 \theta+\cos ^4\theta = (\sin^2 \theta + \cos^2 \theta)^2 - 2(\sin^2 \theta)(\cos^2 \theta)\)
Now, we use the fundamental trigonometric identity: \(\sin^2 \theta + \cos^2 \theta = 1\).
Substitute this into the expression:
\(\sin^4 \theta+\cos ^4\theta = (1)^2 - 2\sin^2 \theta \cos^2 \theta\)
\(\sin^4 \theta+\cos ^4\theta = 1 - 2\sin^2 \theta \cos^2 \theta\)
So, the simplified form of the numerator is \(1 - 2\sin^2 \theta \cos^2 \theta\).
The denominator of the original expression is \(1-2\sin^2\theta.\cos^2\theta\). This is exactly the same as the simplified form of the numerator we found.
Now substitute the simplified numerator back into the original expression:
\(\rm \frac{\sin^4 \theta+\cos ^4\theta}{1-2\sin^2\theta.\cos^2\theta} = \frac{1 - 2\sin^2 \theta \cos^2 \theta}{1 - 2\sin^2 \theta \cos^2 \theta}\)
Assuming the denominator is not zero (which is generally true for real \(\theta\) as explained below), the expression simplifies to:
\(\frac{1 - 2\sin^2 \theta \cos^2 \theta}{1 - 2\sin^2 \theta \cos^2 \theta} = 1\)
The denominator \(1-2\sin^2\theta.\cos^2\theta\) would be zero if \(1 = 2\sin^2\theta.\cos^2\theta\). We know that \(\sin(2\theta) = 2\sin\theta\cos\theta\), so \(\sin^2(2\theta) = 4\sin^2\theta\cos^2\theta\), which means \(\sin^2\theta\cos^2\theta = \frac{\sin^2(2\theta)}{4}\). Substituting this, we get \(1 = 2 \left(\frac{\sin^2(2\theta)}{4}\right) = \frac{\sin^2(2\theta)}{2}\). This means \(\sin^2(2\theta) = 2\). However, the maximum value of \(\sin^2\) of any angle is 1. Since \(\sin^2(2\theta)\) cannot be greater than 1, \(\sin^2(2\theta) = 2\) has no real solution for \(\theta\). Therefore, the denominator \(1-2\sin^2\theta.\cos^2\theta\) is never zero for real values of \(\theta\).
The simplified value of the expression \(\rm \frac{\sin^4 \theta+\cos ^4\theta}{1-2\sin^2\theta.\cos^2\theta}\) is 1.
Our simplified value is 1, which matches option 1.
| Step | Expression | Explanation |
|---|---|---|
| 1 | \(\sin^4 \theta+\cos ^4\theta\) | Start with the numerator. |
| 2 | \((\sin^2 \theta)^2 + (\cos^2 \theta)^2\) | Rewrite using squares. |
| 3 | \((\sin^2 \theta + \cos^2 \theta)^2 - 2\sin^2 \theta \cos^2 \theta\) | Apply \(a^2+b^2 = (a+b)^2 - 2ab\) with \(a=\sin^2\theta, b=\cos^2\theta\). |
| 4 | \((1)^2 - 2\sin^2 \theta \cos^2 \theta\) | Use \(\sin^2 \theta + \cos^2 \theta = 1\). |
| 5 | \(1 - 2\sin^2 \theta \cos^2 \theta\) | Simplify the numerator. |
| 6 | \(\rm \frac{1 - 2\sin^2 \theta \cos^2 \theta}{1-2\sin^2\theta.\cos^2\theta}\) | Substitute the simplified numerator into the original expression. |
| 7 | \(1\) | Cancel the identical numerator and denominator. |
| Identity | Description |
|---|---|
| \(\sin^2 \theta + \cos^2 \theta = 1\) | The fundamental Pythagorean identity relating sine and cosine. |
| \(\sin(2\theta) = 2\sin\theta\cos\theta\) | Double angle identity for sine. Useful for rewriting \(\sin\theta\cos\theta\). |
| \(a^2 + b^2 = (a+b)^2 - 2ab\) | An algebraic identity useful for rewriting sums of squares. |
| \(a^4 + b^4 = (a^2+b^2)^2 - 2a^2b^2\) | A specific application of the previous identity for fourth powers. |
Simplifying trigonometric expressions often involves recognizing patterns and applying fundamental identities. Here are some tips:
By applying these strategies, we can simplify complex trigonometric expressions effectively.
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