If sinθ = \(\frac{4}{5}\) , Find the value of sin3θ
The problem asks us to find the value of sin3θ given that sinθ = \( \frac{4}{5} \). To solve this, we need to use the trigonometric triple angle formula for sine.
The triple angle formula for sin3θ expresses it in terms of sinθ. The formula is:
\[ \sin3\theta = 3\sin\theta - 4\sin^3\theta \]This formula is essential for solving problems involving the sine of a triple angle when the sine of the single angle is known.
We are given sinθ = \( \frac{4}{5} \). We need to substitute this value into the formula for sin3θ.
Substitute \( \sin\theta = \frac{4}{5} \) into the formula \( \sin3\theta = 3\sin\theta - 4\sin^3\theta \):
\[ \sin3\theta = 3\left(\frac{4}{5}\right) - 4\left(\frac{4}{5}\right)^3 \]Let's calculate each part of the expression:
Now, substitute these results back into the formula for sin3θ:
\[ \sin3\theta = \frac{12}{5} - \frac{256}{125} \]To subtract these fractions, we need a common denominator. The least common multiple of 5 and 125 is 125. Convert \( \frac{12}{5} \) to a fraction with a denominator of 125:
\[ \frac{12}{5} = \frac{12 \times 25}{5 \times 25} = \frac{300}{125} \]Now perform the subtraction:
\[ \sin3\theta = \frac{300}{125} - \frac{256}{125} = \frac{300 - 256}{125} = \frac{44}{125} \]The calculated value of sin3θ is \( \frac{44}{125} \).
Let's summarize the steps:
| Step | Description | Calculation |
|---|---|---|
| 1 | Given sinθ | \( \sin\theta = \frac{4}{5} \) |
| 2 | Formula for sin3θ | \( \sin3\theta = 3\sin\theta - 4\sin^3\theta \) |
| 3 | Substitute and calculate \( 3\sin\theta \) | \( 3 \times \frac{4}{5} = \frac{12}{5} \) |
| 4 | Substitute and calculate \( \sin^3\theta \) | \( \left(\frac{4}{5}\right)^3 = \frac{64}{125} \) |
| 5 | Substitute and calculate \( 4\sin^3\theta \) | \( 4 \times \frac{64}{125} = \frac{256}{125} \) |
| 6 | Substitute into formula | \( \frac{12}{5} - \frac{256}{125} \) |
| 7 | Find common denominator and subtract | \( \frac{300}{125} - \frac{256}{125} = \frac{44}{125} \) |
It's helpful to remember common trigonometric identities and formulas for exam preparation. Here are a few related formulas:
| Formula | Description |
|---|---|
| \( \sin^2\theta + \cos^2\theta = 1 \) | Pythagorean Identity |
| \( \sin2\theta = 2\sin\theta\cos\theta \) | Double Angle Formula for Sine |
| \( \cos2\theta = \cos^2\theta - \sin^2\theta \) \( \cos2\theta = 2\cos^2\theta - 1 \) \( \cos2\theta = 1 - 2\sin^2\theta \) |
Double Angle Formulas for Cosine |
| \( \tan2\theta = \frac{2\tan\theta}{1 - \tan^2\theta} \) | Double Angle Formula for Tangent |
| \( \cos3\theta = 4\cos^3\theta - 3\cos\theta \) | Triple Angle Formula for Cosine |
| \( \tan3\theta = \frac{3\tan\theta - \tan^3\theta}{1 - 3\tan^2\theta} \) | Triple Angle Formula for Tangent |
When solving trigonometry problems, especially those involving identities and formulas, consider these tips:
Mastering trigonometric formulas and practicing their application is crucial for success in trigonometry.
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