To find the fractions in ascending order, we need to arrange them from the smallest value to the largest value. We can compare fractions by converting them to decimals or finding a common denominator. Converting to decimals is often simpler for comparison.
Let's convert each fraction provided in the options to its decimal form:
| Fraction | Decimal Value |
$\frac{3}{8}$ | 0.375 |
$\frac{2}{5}$ | 0.4 |
$\frac{9}{11}$ | ~0.81818... |
$\frac{5}{6}$ | ~0.83333... |
$\frac{6}{7}$ | ~0.85714... |
Now, we check the order of these decimal values for each option:
The correct sequence in ascending order is $\frac{3}{8}, \frac{2}{5}, \frac{9}{11}, \frac{5}{6}, \frac{6}{7}$.
Which fraction among the following is the least ?
\(\frac{5}{11}, \frac{7}{12}, \frac{8}{13}, \frac{9}{17}\)
Find the value of the following expression:
\(\frac{{3 \div 1 \times 2 + 5 - 2}}{{3 \times 3 - 2}}\)
Simplify the expression 441 ÷ \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)
If the sum of two positive numbers is 65 and the square root of their product is 26, then the sum of their reciprocals is:
The value of \(9 \div [\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{6}\div(\frac{3}{4}-\frac{1}{3})\;of\;\frac{2}{9}]\) is: