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Question

The numerator of a fraction is increased by $20\%$ and the denominator is decreased by $50\%$. If the resultant fraction is $\frac{5}{6}$, then what will be the original fraction?

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
$\frac{25}{72}$

Let the original fraction be represented as $\frac{x}{y}$.

Adjusting Numerator and Denominator

  • The numerator is increased by 20%: The new numerator becomes $x + 0.20x = 1.20x$.
  • The denominator is decreased by 50%: The new denominator becomes $y - 0.50y = 0.50y$.

Forming the New Fraction

The new fraction is formed by the adjusted numerator and denominator:

$ \text{New Fraction} = \frac{1.20x}{0.50y} $

We are given that this new fraction is equal to $\frac{5}{6}$:

$ \frac{1.20x}{0.50y} = \frac{5}{6} $

Solving for the Original Fraction

To find the original fraction $\frac{x}{y}$, we rearrange the equation:

  • Simplify the coefficients: $\frac{1.2}{0.5} \times \frac{x}{y} = \frac{5}{6}$.
  • Multiply the numerator and denominator of the coefficient by 10 to remove decimals: $\frac{12}{5} \times \frac{x}{y} = \frac{5}{6}$.
  • Isolate $\frac{x}{y}$ by dividing both sides by $\frac{12}{5}$ (which is the same as multiplying by its reciprocal, $\frac{5}{12}$): $ \frac{x}{y} = \frac{5}{6} \div \frac{12}{5} $ $ \frac{x}{y} = \frac{5}{6} \times \frac{5}{12} $ $ \frac{x}{y} = \frac{5 \times 5}{6 \times 12} $ $ \frac{x}{y} = \frac{25}{72} $

Therefore, the original fraction is $\frac{25}{72}$.

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Similar Questions

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    can be written in the form of:
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  3. What is the positive difference between $\frac{5}{16}$ and its reciprocal?
  4. The sum of the numerator and denominator of a fraction is 11. If the numerator is decreased by 1, the fraction becomes $\frac{1}{4}$. Find the fraction.
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  6. Solve the following:

    $(0.\overline{5} + 0.\overline{6} + 0.\overline{7} + 0.\overline{8}) = ?$
  7. What is the sum of $\frac{1}{3}$, $\frac{4}{3}$ and $\frac{3}{4}$?
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Important Questions from Fractions

  1. Which fraction among the following is the least ?

    \(\frac{5}{11}, \frac{7}{12}, \frac{8}{13}, \frac{9}{17}\)

  2. Find the value of the following expression:

    \(\frac{{3 \div 1 \times 2 + 5 - 2}}{{3 \times 3 - 2}}\)

  3. Simplify the expression 441 ÷  \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)

  4. If the sum of two positive numbers is 65 and the square root of their product is 26, then the sum of their reciprocals is:

  5. The value of \(9 \div [\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{6}\div(\frac{3}{4}-\frac{1}{3})\;of\;\frac{2}{9}]\)  is:

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