Let the original fraction be represented as $\frac{x}{y}$.
The new fraction is formed by the adjusted numerator and denominator:
$ \text{New Fraction} = \frac{1.20x}{0.50y} $We are given that this new fraction is equal to $\frac{5}{6}$:
$ \frac{1.20x}{0.50y} = \frac{5}{6} $To find the original fraction $\frac{x}{y}$, we rearrange the equation:
Therefore, the original fraction is $\frac{25}{72}$.
Which fraction among the following is the least ?
\(\frac{5}{11}, \frac{7}{12}, \frac{8}{13}, \frac{9}{17}\)
Find the value of the following expression:
\(\frac{{3 \div 1 \times 2 + 5 - 2}}{{3 \times 3 - 2}}\)
Simplify the expression 441 ÷ \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)
If the sum of two positive numbers is 65 and the square root of their product is 26, then the sum of their reciprocals is:
The value of \(9 \div [\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{6}\div(\frac{3}{4}-\frac{1}{3})\;of\;\frac{2}{9}]\) is: