Direction: The given table represents the marks obtained by four students W, X, Y and Z in four subjects P, C, B and M, with the maximum marks in each subject being 100. Study the table carefully and answer the following question. Stu/Sub P C B M W 70 90 50 85 X 55 80 95 60 Y 60 20 90 40 Z 90 80 40 65
What is the average marks of the four students in P?
68.75
Calculating Average Marks from Table Data
The question asks for the average marks obtained by four students (W, X, Y, and Z) in subject P, based on the provided table. The table shows the marks of these students in four different subjects: P, C, B, and M. To find the average marks in subject P, we need to identify the marks of each student specifically in subject P, sum them up, and then divide by the total number of students.
| Stu/Sub | P | C | B | M |
|---|---|---|---|---|
| W | 70 | 90 | 50 | 85 |
| X | 55 | 80 | 95 | 60 |
| Y | 60 | 20 | 90 | 40 |
| Z | 90 | 80 | 40 | 65 |
Identifying Marks in Subject P
From the table, we can find the marks obtained by each student in subject P:
- Student W's marks in P: 70
- Student X's marks in P: 55
- Student Y's marks in P: 60
- Student Z's marks in P: 90
Calculating the Sum of Marks in Subject P
Next, we add the marks of all four students in subject P:
\text{Total marks in P} = 70 + 55 + 60 + 90
\text{Total marks in P} = 125 + 60 + 90
\text{Total marks in P} = 185 + 90
\text{Total marks in P} = 275
Determining the Number of Students
There are four students listed: W, X, Y, and Z. So, the number of students is 4.
Calculating the Average Marks in Subject P
The formula for average is the sum of values divided by the number of values. In this case, it's the total marks in subject P divided by the number of students:
\text{Average marks in P} = \frac{\text{Total marks in P}}{\text{Number of students}}
\text{Average marks in P} = \frac{275}{4}
Let's perform the division:
\frac{275}{4} = 68.75
So, the average marks of the four students in subject P is 68.75.
Comparing with Options
Let's look at the given options:
- 68.5
- 68.25
- 68
- 68.75
Our calculated average mark of 68.75 matches option 4.
Revision Table: Key Calculation Steps
| Step | Description | Value/Calculation |
|---|---|---|
| 1 | Marks in Subject P for each student | W=70, X=55, Y=60, Z=90 |
| 2 | Sum of marks in Subject P | \(70 + 55 + 60 + 90 = 275\) |
| 3 | Number of students | 4 |
| 4 | Average marks in P | \(\frac{275}{4} = 68.75\) |
Additional Information: Understanding Averages and Data Interpretation
Calculating the average is a fundamental concept in statistics and data analysis. The average, specifically the arithmetic mean, provides a central value that summarizes a set of data. In this problem, calculating the average marks in subject P gives us a single value that represents the typical performance of the four students in that subject.
- Data Interpretation: This question requires interpreting data presented in a table. Reading tables accurately, extracting relevant information (like marks in a specific subject for specific students), and performing calculations based on this data are key skills.
- Arithmetic Mean: The average calculated here is the arithmetic mean. It is found by summing all the values in a dataset and dividing by the number of values in the dataset. The formula is: Average = (Sum of values) / (Number of values).
- Applications: Calculating averages is useful in many real-world scenarios, such as finding the average temperature over a week, average income in a city, or average scores on a test. It helps in comparing performance or understanding typical trends.
Similar Questions
Direction: A table is given below, study the table carefully and answer the following question.
The given table represents the marks obtained by four students W. X, Y and Z in four subjects P, C, B and M. with the maximum marks in each subject being 100.
Stu/sub
P
C
B
M
W
70
90
50
85
X
55
80
95
60
Y
60
20
90
40
Z
90
80
40
65
The difference between the highest and the lowest percentage (P, C, M and B together) among the four students is:
Direction: The following table gives the details of the number of students in Class 10, Section A and B, who had taken the midterm and final exams.
Result
Section A
Section B
Total number of students who failed in both the exams
28
23
Number of students who failed in the
midterm but passed in the final exam
14
12
Number of students who passed in the
midterm but failed in the final exam
6
17
Number of students who passed in both the exams
64
55
Based on the given data, the percentage of Section A students who passed the annual exam is_____.
- The given table represents the marks obtained by four students W, X, Y and Z in four subjects P, C, B and M with the maximum in each subject being 100
Stu/sub
P
C
B
M
W
70
90
50
85
X
55
80
95
60
Y
60
20
90
40
Z
90
80
40
65
Based on the given data. Find W's marks percentage in P, C and B combined together. Based on the given table, the percentage salary increase during the period 2001-2006 was (round off to the nearest integer).
Direction: The given table represents the marks obtained by four students W, X, Y and Z in four subjects P, C, B and M , the maximum marks in each subject being 100.
Stu/sub
P
C
B
M
W
70
90
50
85
X
55
80
95
60
Y
60
20
90
40
Z
90
80
40
65
Based on the given data, the student who got the lowest percentage in P, C, M, and B combined is:
Direction: The given table represents the marks obtained by four students W, X, Y and Z in four subjects P, C, B and M and the maximum marks in each subject being 100.
Stu/sub
P
C
B
M
W
70
90
50
85
X
55
80
95
60
Y
60
20
90
40
Z
90
80
40
65
The average marks of the four students in M is:
The following table shows the gain in weight by 25 children in a year. What is the mean value of gain in weight?
Gain in weight (in kg) No. of children 1.5 4 2 5 2.4 8 3 5 3.2 2 3.4 1 The total percentage of illiterates in all the four cities is _______ (round to one decimal place).
City
Population
Literate
illiterate
% of literate
A
200
150
50
-
B
-
200
100
66.6
C
150
50
100
-
D
120
-
90
25
Important Questions from Tabulation
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Find the difference between the total number of patients recovered from Covid-19 in all months in Punjab and the total number of patients recovered from Covid-19 in all months in Rajasthan.
In February 2021 the number of patients recovered from Covid-19 in Punjab is how much approximant percent more/less than the number of patients recovered from Covid-19 Uttar Pradesh in the same month?
