Direction: A table is given below, study the table carefully and answer the following question. Year Items of Expenditure Salary Food Medicine Tax 2001 Rs. 1,500 Rs. 200 Rs. 500 Rs. 100 2002 Rs. 2,600 Rs. 300 Rs. 600 Rs. 200 2003 Rs. 3,200 Rs. 150 Rs. 700 Rs. 150 2004 Rs. 4,100 Rs. 250 Rs. 650 Rs. 125 2005 Rs. 5,000 Rs. 200 Rs. 800 Rs. 150 2006 Rs. 5,200 Rs. 100 Rs. 750 Rs. 175
Based on the given table, the percentage salary increase during the period 2001-2006 was (round off to the nearest integer).
247%
Understanding the Expenditure Table
The question asks us to analyze the provided table which details various items of expenditure over several years, from 2001 to 2006. Specifically, we need to focus on the 'Salary' column to determine the percentage increase in salary during this period.
| Year | Items of Expenditure | Salary (Rs.) | Food (Rs.) | Medicine (Rs.) | Tax (Rs.) |
|---|---|---|---|---|---|
| 2001 | 1,500 | 200 | 500 | 100 | |
| 2002 | 2,600 | 300 | 600 | 200 | |
| 2003 | 3,200 | 150 | 700 | 150 | |
| 2004 | 4,100 | 250 | 650 | 125 | |
| 2005 | 5,000 | 200 | 800 | 150 | |
| 2006 | 5,200 | 100 | 750 | 175 |
Calculating Salary Increase (2001-2006)
We need to find the percentage salary increase from the beginning of the period (2001) to the end of the period (2006). This involves identifying the salary values for these two years and applying the percentage change formula.
From the table:
- Salary in 2001 = Rs. 1,500
- Salary in 2006 = Rs. 5,200
The percentage increase is calculated using the formula:
$$\text{Percentage Increase} = \left( \frac{\text{Final Value} - \text{Initial Value}}{\text{Initial Value}} \right) \times 100$$
In this case, the Initial Value is the salary in 2001 and the Final Value is the salary in 2006.
Let's plug in the values:
$$\text{Salary Increase} = \left( \frac{5200 - 1500}{1500} \right) \times 100$$
$$\text{Salary Increase} = \left( \frac{3700}{1500} \right) \times 100$$
$$\text{Salary Increase} = \left( \frac{37}{15} \right) \times 100$$
Now, we calculate the value:
$$\frac{37}{15} \approx 2.4666...$$
$$\text{Salary Increase} \approx 2.4666... \times 100$$
$$\text{Salary Increase} \approx 246.66... \%$$
The question asks to round off the percentage salary increase to the nearest integer. Rounding 246.66...% to the nearest integer gives 247%.
Revision Table: Key Calculations
| Description | Value |
|---|---|
| Salary in 2001 (Initial) | Rs. 1,500 |
| Salary in 2006 (Final) | Rs. 5,200 |
| Absolute Increase | Rs. 5200 - Rs. 1500 = Rs. 3700 |
| Percentage Increase Calculation | $$(3700 / 1500) \times 100$$ |
| Calculated Percentage Increase | $$246.66... \%$$ |
| Rounded Percentage Increase | 247% |
Additional Information: Percentage Change Concepts
Understanding percentage change is crucial in analyzing data trends over time. It helps us compare relative changes, regardless of the initial magnitude of the values.
- Percentage Increase: Used when a value grows over time. The formula is $\frac{\text{New Value} - \text{Original Value}}{\text{Original Value}} \times 100$.
- Percentage Decrease: Used when a value reduces over time. The formula is $\frac{\text{Original Value} - \text{New Value}}{\text{Original Value}} \times 100$. Notice the original value is still the denominator, and the difference is positive.
- Base Value: The denominator in the percentage change calculation is always the original or starting value. This is important for correct interpretation.
In this problem, we calculated the percentage salary increase using the salary in 2001 as the base (original value).
Similar Questions
What is the average marks of the four students in P?
Direction: A table is given below, study the table carefully and answer the following question.
The given table represents the marks obtained by four students W. X, Y and Z in four subjects P, C, B and M. with the maximum marks in each subject being 100.
Stu/sub
P
C
B
M
W
70
90
50
85
X
55
80
95
60
Y
60
20
90
40
Z
90
80
40
65
The difference between the highest and the lowest percentage (P, C, M and B together) among the four students is:
The following table shows the gain in weight by 25 children in a year. What is the mean value of gain in weight?
Gain in weight (in kg) No. of children 1.5 4 2 5 2.4 8 3 5 3.2 2 3.4 1 Direction: The following table gives the details of the number of students in Class 10, Section A and B, who had taken the midterm and final exams.
Result
Section A
Section B
Total number of students who failed in both the exams
28
23
Number of students who failed in the
midterm but passed in the final exam
14
12
Number of students who passed in the
midterm but failed in the final exam
6
17
Number of students who passed in both the exams
64
55
Based on the given data, the percentage of Section A students who passed the annual exam is_____.
- The given table represents the marks obtained by four students W, X, Y and Z in four subjects P, C, B and M with the maximum in each subject being 100
Stu/sub
P
C
B
M
W
70
90
50
85
X
55
80
95
60
Y
60
20
90
40
Z
90
80
40
65
Based on the given data. Find W's marks percentage in P, C and B combined together. The total percentage of illiterates in all the four cities is _______ (round to one decimal place).
City
Population
Literate
illiterate
% of literate
A
200
150
50
-
B
-
200
100
66.6
C
150
50
100
-
D
120
-
90
25
Direction: The given table represents the marks obtained by four students W, X, Y and Z in four subjects P, C, B and M , the maximum marks in each subject being 100.
Stu/sub
P
C
B
M
W
70
90
50
85
X
55
80
95
60
Y
60
20
90
40
Z
90
80
40
65
Based on the given data, the student who got the lowest percentage in P, C, M, and B combined is:
Direction: The given table represents the marks obtained by four students W, X, Y and Z in four subjects P, C, B and M and the maximum marks in each subject being 100.
Stu/sub
P
C
B
M
W
70
90
50
85
X
55
80
95
60
Y
60
20
90
40
Z
90
80
40
65
The average marks of the four students in M is:
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