Direction: The given table represents the marks obtained by four students W, X, Y and Z in four subjects P, C, B and M and the maximum marks in each subject being 100. Stu/sub P C B M W 70 90 50 85 X 55 80 95 60 Y 60 20 90 40 Z 90 80 40 65 The average marks of the four students in M is:
62.5
Calculating Average Marks from Table Data
The question asks us to find the average marks obtained by four students (W, X, Y, and Z) specifically in subject M, using the data provided in the table.
| Stu/sub | P | C | B | M |
|---|---|---|---|---|
| W | 70 | 90 | 50 | 85 |
| X | 55 | 80 | 95 | 60 |
| Y | 60 | 20 | 90 | 40 |
| Z | 90 | 80 | 40 | 65 |
Understanding Average
The average of a set of numbers is calculated by summing all the numbers in the set and then dividing the sum by the count of numbers in the set.
The formula for the average (or mean) is:
$$\text{Average} = \frac{\text{Sum of all values}}{\text{Number of values}}$$
Finding Marks in Subject M
We need to identify the marks obtained by each student in subject M from the table. Looking at the 'M' column:
- Student W's marks in M = 85
- Student X's marks in M = 60
- Student Y's marks in M = 40
- Student Z's marks in M = 65
Calculating the Sum of Marks in M
Now, we add up the marks of all four students in subject M:
Sum of marks in M = Marks of W + Marks of X + Marks of Y + Marks of Z
Sum of marks in M = $$85 + 60 + 40 + 65$$
Let's calculate the sum:
$$85 + 60 = 145$$
$$145 + 40 = 185$$
$$185 + 65 = 250$$
So, the total sum of marks in subject M for the four students is 250.
Calculating the Average Marks in M
There are 4 students (W, X, Y, Z). The number of students is 4.
Average marks in M = $$\frac{\text{Sum of marks in M}}{\text{Number of students}}$$
Average marks in M = $$\frac{250}{4}$$
Now, we perform the division:
$$250 \div 4 = 62.5$$
The average marks of the four students in subject M is 62.5.
Comparing with Options
Let's look at the given options:
- 62.25
- 62.5
- 62.75
- 62
Our calculated average is 62.5, which matches option 2.
Revision Table: Key Concepts for Average Calculation
| Concept | Description |
|---|---|
| Average (Mean) | A measure of central tendency; sum of values divided by the count of values. |
| Summation | Adding all numbers in a set. |
| Count | The total number of items in a set. |
Additional Information: Analyzing Table Data and Averages
Analyzing tables like this helps in understanding data distribution and performance. Calculating averages is a common way to summarize performance for a group or in a specific area.
- Calculating average marks for each student across all subjects gives insight into individual performance.
- Calculating average marks for each subject across all students (as we did for M) gives insight into the difficulty or overall performance in that subject.
- Comparing averages can help identify strengths and weaknesses.
Understanding how to extract specific data points from a table and apply basic mathematical operations like summation and division is crucial for data interpretation tasks.
Similar Questions
What is the average marks of the four students in P?
Direction: A table is given below, study the table carefully and answer the following question.
The given table represents the marks obtained by four students W. X, Y and Z in four subjects P, C, B and M. with the maximum marks in each subject being 100.
Stu/sub
P
C
B
M
W
70
90
50
85
X
55
80
95
60
Y
60
20
90
40
Z
90
80
40
65
The difference between the highest and the lowest percentage (P, C, M and B together) among the four students is:
Direction: The following table gives the details of the number of students in Class 10, Section A and B, who had taken the midterm and final exams.
Result
Section A
Section B
Total number of students who failed in both the exams
28
23
Number of students who failed in the
midterm but passed in the final exam
14
12
Number of students who passed in the
midterm but failed in the final exam
6
17
Number of students who passed in both the exams
64
55
Based on the given data, the percentage of Section A students who passed the annual exam is_____.
- The given table represents the marks obtained by four students W, X, Y and Z in four subjects P, C, B and M with the maximum in each subject being 100
Stu/sub
P
C
B
M
W
70
90
50
85
X
55
80
95
60
Y
60
20
90
40
Z
90
80
40
65
Based on the given data. Find W's marks percentage in P, C and B combined together. Based on the given table, the percentage salary increase during the period 2001-2006 was (round off to the nearest integer).
Direction: The given table represents the marks obtained by four students W, X, Y and Z in four subjects P, C, B and M , the maximum marks in each subject being 100.
Stu/sub
P
C
B
M
W
70
90
50
85
X
55
80
95
60
Y
60
20
90
40
Z
90
80
40
65
Based on the given data, the student who got the lowest percentage in P, C, M, and B combined is:
The following table shows the gain in weight by 25 children in a year. What is the mean value of gain in weight?
Gain in weight (in kg) No. of children 1.5 4 2 5 2.4 8 3 5 3.2 2 3.4 1 The total percentage of illiterates in all the four cities is _______ (round to one decimal place).
City
Population
Literate
illiterate
% of literate
A
200
150
50
-
B
-
200
100
66.6
C
150
50
100
-
D
120
-
90
25
Important Questions from Tabulation
What is the ratio of total number of patients recovered from covid-19 in April to total number of patients recovered from covid-19 in March?
In which state, the number of patients who recovered from covid-19 steadily decreasing?
What is the average number of patients who recovered from Covid-19 in Madhya Pradesh in four months?
Find the difference between the total number of patients recovered from Covid-19 in all months in Punjab and the total number of patients recovered from Covid-19 in all months in Rajasthan.
In February 2021 the number of patients recovered from Covid-19 in Punjab is how much approximant percent more/less than the number of patients recovered from Covid-19 Uttar Pradesh in the same month?
