Stu/sub P C B M W 70 90 50 85 X 55 80 95 60 Y 60 20 90 40 Z 90 80 40 65
Based on the given data. Find W's marks percentage in P, C and B combined together.
70
Calculating Student Marks Percentage
This question asks us to determine the combined marks percentage obtained by student W in three specific subjects: P, C, and B. We are given the marks of four students (W, X, Y, Z) in four subjects (P, C, B, M), with the maximum marks for each subject being 100.
Analyzing the Provided Student Marks Data
The data provided needs to be structured for clarity. It lists students and their marks per subject. Let's organize this information into a table.
| Student / Subject | P (Max 100) | C (Max 100) | B (Max 100) | M (Max 100) |
|---|---|---|---|---|
| W | 70 | 90 | 50 | 85 |
| X | 55 | 80 | 95 | 60 |
| Y | 60 | 20 | 90 | 40 |
| Z | 90 | 80 | 40 | 65 |
Focusing on W's Marks in P, C, and B
We need to find W's combined percentage in subjects P, C, and B. First, let's identify W's marks in these specific subjects from the table:
- W's marks in Subject P: 70
- W's marks in Subject C: 90
- W's marks in Subject B: 50
Calculating Total Obtained Marks for W
To find the combined percentage, we first need the total marks W obtained in these three subjects. We add the marks from Subject P, Subject C, and Subject B:
Total Marks Obtained = W's Marks (P) + W's Marks (C) + W's Marks (B)
Total Marks Obtained = $70 + 90 + 50 = 210$
Calculating Total Maximum Marks for P, C, and B
Next, we need to find the total maximum possible marks for these three subjects combined. The maximum marks for each subject is 100. So, for three subjects:
Total Maximum Marks = Maximum Marks (P) + Maximum Marks (C) + Maximum Marks (B)
Total Maximum Marks = $100 + 100 + 100 = 300$
Calculating W's Combined Percentage
Now that we have the total marks obtained by W and the total maximum marks for the combined subjects (P, C, and B), we can calculate the percentage using the formula:
Percentage = $\left( \frac{\text{Total Marks Obtained}}{\text{Total Maximum Marks}} \right) \times 100$
Percentage = $\left( \frac{210}{300} \right) \times 100$
Let's simplify the fraction:
Percentage = $\left( \frac{21}{30} \right) \times 100$
Further simplification by dividing both numerator and denominator by 3:
Percentage = $\left( \frac{7}{10} \right) \times 100$
Percentage = $0.7 \times 100$
Percentage = $70$
So, W's marks percentage in P, C, and B combined together is 70%.
Revision Table: Key Calculation Steps
| Step | Description | Value |
|---|---|---|
| 1 | W's marks in P, C, B | 70, 90, 50 |
| 2 | Total marks obtained by W (P+C+B) | $70 + 90 + 50 = 210$ |
| 3 | Maximum marks for P, C, B | 100, 100, 100 |
| 4 | Total maximum marks (P+C+B) | $100 + 100 + 100 = 300$ |
| 5 | Combined Percentage | $\left( \frac{210}{300} \right) \times 100 = 70\%$ |
Additional Information on Percentage Calculation
Calculating percentages is a fundamental skill used widely in academics and daily life. A percentage is a number or ratio expressed as a fraction of 100. It is often denoted using the percent sign, "%".
The general formula to calculate percentage is:
Percentage = $\left( \frac{\text{Part}}{\text{Whole}} \right) \times 100$
In the context of marks, the 'Part' is the marks obtained by the student, and the 'Whole' is the maximum possible marks.
Understanding percentages helps compare performance across different tests or subjects, even if the maximum marks are different. In this case, calculating the combined percentage for specific subjects gives a clearer picture of performance in that group of subjects.
Similar Questions
What is the average marks of the four students in P?
Direction: A table is given below, study the table carefully and answer the following question.
The given table represents the marks obtained by four students W. X, Y and Z in four subjects P, C, B and M. with the maximum marks in each subject being 100.
Stu/sub
P
C
B
M
W
70
90
50
85
X
55
80
95
60
Y
60
20
90
40
Z
90
80
40
65
The difference between the highest and the lowest percentage (P, C, M and B together) among the four students is:
Direction: The following table gives the details of the number of students in Class 10, Section A and B, who had taken the midterm and final exams.
Result
Section A
Section B
Total number of students who failed in both the exams
28
23
Number of students who failed in the
midterm but passed in the final exam
14
12
Number of students who passed in the
midterm but failed in the final exam
6
17
Number of students who passed in both the exams
64
55
Based on the given data, the percentage of Section A students who passed the annual exam is_____.
Based on the given table, the percentage salary increase during the period 2001-2006 was (round off to the nearest integer).
Direction: The given table represents the marks obtained by four students W, X, Y and Z in four subjects P, C, B and M , the maximum marks in each subject being 100.
Stu/sub
P
C
B
M
W
70
90
50
85
X
55
80
95
60
Y
60
20
90
40
Z
90
80
40
65
Based on the given data, the student who got the lowest percentage in P, C, M, and B combined is:
Direction: The given table represents the marks obtained by four students W, X, Y and Z in four subjects P, C, B and M and the maximum marks in each subject being 100.
Stu/sub
P
C
B
M
W
70
90
50
85
X
55
80
95
60
Y
60
20
90
40
Z
90
80
40
65
The average marks of the four students in M is:
The following table shows the gain in weight by 25 children in a year. What is the mean value of gain in weight?
Gain in weight (in kg) No. of children 1.5 4 2 5 2.4 8 3 5 3.2 2 3.4 1 The total percentage of illiterates in all the four cities is _______ (round to one decimal place).
City
Population
Literate
illiterate
% of literate
A
200
150
50
-
B
-
200
100
66.6
C
150
50
100
-
D
120
-
90
25
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