Direction: The given table represents the marks obtained by four students W, X, Y and Z in four subjects P, C, B and M , the maximum marks in each subject being 100. Stu/sub P C B M W 70 90 50 85 X 55 80 95 60 Y 60 20 90 40 Z 90 80 40 65 Based on the given data, the student who got the lowest percentage in P, C, M, and B combined is:
Y
Analyzing Student Performance from the Marks Table
The question asks us to identify the student who achieved the lowest combined percentage across four subjects: P, C, B, and M. We are given a table showing the marks obtained by four students (W, X, Y, and Z) in these four subjects. The maximum marks for each subject is 100.
First, let's look at the provided marks table:
| Stu/Sub | P | C | B | M |
|---|---|---|---|---|
| W | 70 | 90 | 50 | 85 |
| X | 55 | 80 | 95 | 60 |
| Y | 60 | 20 | 90 | 40 |
| Z | 90 | 80 | 40 | 65 |
Calculating Combined Percentage for Students
To find the student with the lowest combined percentage, we need to calculate the total marks obtained by each student across the four subjects and then determine their percentage.
Since the maximum marks for each subject is 100, the total maximum marks for the four subjects combined is $100 \times 4 = 400$.
The combined percentage for a student is calculated using the formula:
$\text{Combined Percentage} = \frac{\text{Total Marks Obtained}}{\text{Total Maximum Marks}} \times 100\%$
Let's calculate the total marks and combined percentage for each student:
- Student W:
- Total Marks = Marks in P + Marks in C + Marks in B + Marks in M
- Total Marks for W = $70 + 90 + 50 + 85 = 295$
- Combined Percentage for W = $\frac{295}{400} \times 100\% = 0.7375 \times 100\% = 73.75\%$
- Student X:
- Total Marks = Marks in P + Marks in C + Marks in B + Marks in M
- Total Marks for X = $55 + 80 + 95 + 60 = 290$
- Combined Percentage for X = $\frac{290}{400} \times 100\% = 0.725 \times 100\% = 72.5\%$
- Student Y:
- Total Marks = Marks in P + Marks in C + Marks in B + Marks in M
- Total Marks for Y = $60 + 20 + 90 + 40 = 210$
- Combined Percentage for Y = $\frac{210}{400} \times 100\% = 0.525 \times 100\% = 52.5\%$
- Student Z:
- Total Marks = Marks in P + Marks in C + Marks in B + Marks in M
- Total Marks for Z = $90 + 80 + 40 + 65 = 275$
- Combined Percentage for Z = $\frac{275}{400} \times 100\% = 0.6875 \times 100\% = 68.75\%$
Comparing the Combined Percentages
Now we compare the calculated combined percentages for all four students:
- Student W: 73.75%
- Student X: 72.5%
- Student Y: 52.5%
- Student Z: 68.75%
By comparing these percentages, we can see that the lowest combined percentage is 52.5%, which was obtained by Student Y.
Therefore, Student Y got the lowest percentage in subjects P, C, M, and B combined.
The final answer is Y.
Revision Table: Student Performance Summary
| Student | Total Marks (P+C+B+M) | Total Maximum Marks | Combined Percentage |
|---|---|---|---|
| W | 295 | 400 | 73.75% |
| X | 290 | 400 | 72.5% |
| Y | 210 | 400 | 52.5% |
| Z | 275 | 400 | 68.75% |
Additional Information: Understanding Percentages
A percentage is a way to express a number as a fraction of 100. It is often used to represent proportions or parts of a whole. In the context of marks, percentage indicates the proportion of marks obtained out of the total possible marks, expressed as a value out of 100.
The formula for calculating percentage is:
$\text{Percentage} = \frac{\text{Part}}{\text{Whole}} \times 100\%$
In this problem, the 'Part' is the total marks obtained by the student, and the 'Whole' is the total maximum marks for the combined subjects. Calculating percentages helps in comparing performance across different students or subjects, even if the total possible marks are different (though in this case, the total max marks are the same for all students).
Comparing percentages is useful because it standardizes the scores, allowing for a fair comparison regardless of the total scale. A lower percentage indicates a lower score relative to the maximum possible score.
Similar Questions
What is the average marks of the four students in P?
Direction: A table is given below, study the table carefully and answer the following question.
The given table represents the marks obtained by four students W. X, Y and Z in four subjects P, C, B and M. with the maximum marks in each subject being 100.
Stu/sub
P
C
B
M
W
70
90
50
85
X
55
80
95
60
Y
60
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90
40
Z
90
80
40
65
The difference between the highest and the lowest percentage (P, C, M and B together) among the four students is:
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Result
Section A
Section B
Total number of students who failed in both the exams
28
23
Number of students who failed in the
midterm but passed in the final exam
14
12
Number of students who passed in the
midterm but failed in the final exam
6
17
Number of students who passed in both the exams
64
55
Based on the given data, the percentage of Section A students who passed the annual exam is_____.
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Stu/sub
P
C
B
M
W
70
90
50
85
X
55
80
95
60
Y
60
20
90
40
Z
90
80
40
65
Based on the given data. Find W's marks percentage in P, C and B combined together. Based on the given table, the percentage salary increase during the period 2001-2006 was (round off to the nearest integer).
Direction: The given table represents the marks obtained by four students W, X, Y and Z in four subjects P, C, B and M and the maximum marks in each subject being 100.
Stu/sub
P
C
B
M
W
70
90
50
85
X
55
80
95
60
Y
60
20
90
40
Z
90
80
40
65
The average marks of the four students in M is:
The following table shows the gain in weight by 25 children in a year. What is the mean value of gain in weight?
Gain in weight (in kg) No. of children 1.5 4 2 5 2.4 8 3 5 3.2 2 3.4 1 The total percentage of illiterates in all the four cities is _______ (round to one decimal place).
City
Population
Literate
illiterate
% of literate
A
200
150
50
-
B
-
200
100
66.6
C
150
50
100
-
D
120
-
90
25
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