Two circles are defined as orthogonal if they intersect each other. The angle between them is specifically measured at their intersection points.
The angle between two intersecting circles is technically the angle formed by their tangents at the point of intersection.
A crucial geometric condition for orthogonality is that the radii drawn from the centers to an intersection point are perpendicular to each other. This geometric property directly defines the angle.
When the radii to the intersection point are perpendicular (forming a 90-degree angle), the tangents at that point are also perpendicular. Therefore, the angle between the two circles is a right angle.
Correct Answer: Option D - right angle
A circle having centre $c_1$, radius $r_1$ = 5 cm is placed against a right angle. Another smaller circle having centre $c_2$, radius $r_2$ is also placed touching the sides of angle and the bigger circle as shown in the figure. Find the radius, $r_2$ in cm, of the smaller circle.
In the given circle with centre O, the obtuse angle at the centre measures $104^\circ$. In the quadrilateral drawn inside the circle, what is the measure of the angle opposite to $\angle\text{O}$? [Figure is not drawn to scale.]
If 3x + y - 5 = 0 is the equation of a chord of the circle x2 + y2 - 25 = 0, then what are the coordinates of the mid-point of the chord ?
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