To find the length of the arc of a sector, we use the formula:
Arc Length, $L = \frac{\theta}{360°} \times 2\pi r$
Where:
Given:
Substitute the values into the formula:
$L = \frac{30°}{360°} \times 2 \times \frac{22}{7} \times 42 \text{ cm}$
$\frac{30°}{360°} = \frac{1}{12}$
$L = \frac{1}{12} \times 2 \times \frac{22}{7} \times 42 \text{ cm}$
$L = \frac{1}{12} \times 2 \times 22 \times \frac{42}{7} \text{ cm}$
$L = \frac{1}{12} \times 2 \times 22 \times 6 \text{ cm}$
$L = \frac{1}{12} \times 264 \text{ cm}$
$L = 22 \text{ cm}$
Therefore, the length of the arc of the sector is 22 cm.
A park is designed in the shape of a right-angled triangle, where the two shorter sides measure 13 m and 84 m. A circular track with a uniform width of 2 m is constructed such that its outer boundary coincides with the circumcircle of the triangular park. Determine the perimeter of the inner boundary of this circular track.
The sum of the radius and diameter of a circle is 84 cm. What is the circumference of this circle?
The maximum area of a right-angled triangle inscribed in a circle of radius r is
The tangent at a point C of a circle and diameter AB when extended intersect at D, if ∠DCA = 110°, then ∠CBA is equal to
The equation of a circle with diameters are 2x - 3y + 12 = 0 and x + 4y - 5 = 0 and area of 154 sq. units is
The internal center of similitude of two circles $ (x - 1)^2 + (y - 3)^2 = 4 $ and $ (x + 5)^2 + (y - 9)^2 = 16 $ is