Triangles \(PQR\) and \(ABC\) are similar triangles. Triangle \(ABC\) have the following sides \(AB = 12 \text{ cm}\), \(AC = 15 \text{ cm}\), \(CB = 21 \text{ cm}\). Triangle \(PQR\) have the following sides: \(PQ = 4 \text{ cm}\), \(RQ = 7 \text{ cm}\). What is the length of side \(PR\)?
We are given two similar triangles, \(PQR\) and \(ABC\). The side lengths for triangle \(ABC\) are \(AB = 12 \text{ cm}\), \(AC = 15 \text{ cm}\), and \(CB = 21 \text{ cm}\). The side lengths for triangle \(PQR\) are \(PQ = 4 \text{ cm}\) and \(RQ = 7 \text{ cm}\). We need to find the length of side \(PR\).
Since triangles \(PQR\) and \(ABC\) are similar (denoted as \(PQR \sim ABC\)), their corresponding sides are in proportion. The correspondence is \(P \leftrightarrow A\), \(Q \leftrightarrow B\), and \(R \leftrightarrow C\). Therefore, the ratios of corresponding sides are equal:
\(\frac{PQ}{AB} = \frac{QR}{BC} = \frac{PR}{AC}\)
We can use the known sides to find the scale factor between the two triangles.
\(\frac{PQ}{AB} = \frac{4 \text{ cm}}{12 \text{ cm}} = \frac{1}{3}\)
\(\frac{RQ}{CB} = \frac{7 \text{ cm}}{21 \text{ cm}} = \frac{1}{3}\)
Both ratios confirm the scale factor is \(\frac{1}{3}\). Triangle \(PQR\) is smaller than triangle \(ABC\).
Now we use the similarity ratio involving the side \(PR\) and its corresponding side \(AC\):
\(\frac{PR}{AC} = \frac{1}{3}\)
Substitute the known length of \(AC = 15 \text{ cm}\):
\(\frac{PR}{15 \text{ cm}} = \frac{1}{3}\)
To find \(PR\), multiply both sides by \(15 \text{ cm}\):
\(PR = \frac{1}{3} \times 15 \text{ cm}\)
\(PR = 5 \text{ cm}\)
Thus, the length of side \(PR\) is \(5 \text{ cm}\).
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