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Question

Triangles \(PQR\) and \(ABC\) are similar triangles. Triangle \(ABC\) have the following sides 

\(AB = 12 \text{ cm}\)

\(AC = 15 \text{ cm}\)

\(CB = 21 \text{ cm}\)

Triangle \(PQR\) have the following sides: 

\(PQ = 4 \text{ cm}\)

\(RQ = 7 \text{ cm}\)

What is the length of side \(PR\)?

This question was previously asked in
RRB ALP 2018 CBT 2 Fitter Question Paper (21-Jan-2019) (Shift 3)
The correct answer is
5 cm

Similar Triangles: Finding Side PR Length

We are given two similar triangles, \(PQR\) and \(ABC\). The side lengths for triangle \(ABC\) are \(AB = 12 \text{ cm}\), \(AC = 15 \text{ cm}\), and \(CB = 21 \text{ cm}\). The side lengths for triangle \(PQR\) are \(PQ = 4 \text{ cm}\) and \(RQ = 7 \text{ cm}\). We need to find the length of side \(PR\).

Similarity Ratios

Since triangles \(PQR\) and \(ABC\) are similar (denoted as \(PQR \sim ABC\)), their corresponding sides are in proportion. The correspondence is \(P \leftrightarrow A\), \(Q \leftrightarrow B\), and \(R \leftrightarrow C\). Therefore, the ratios of corresponding sides are equal:

\(\frac{PQ}{AB} = \frac{QR}{BC} = \frac{PR}{AC}\)

Calculating the Ratio Factor

We can use the known sides to find the scale factor between the two triangles.

  • Ratio using sides \(PQ\) and \(AB\):

    \(\frac{PQ}{AB} = \frac{4 \text{ cm}}{12 \text{ cm}} = \frac{1}{3}\)

  • Ratio using sides \(RQ\) (which is the same as \(QR\)) and \(CB\) (which is the same as \(BC\)):

    \(\frac{RQ}{CB} = \frac{7 \text{ cm}}{21 \text{ cm}} = \frac{1}{3}\)

Both ratios confirm the scale factor is \(\frac{1}{3}\). Triangle \(PQR\) is smaller than triangle \(ABC\).

Finding the Length of PR

Now we use the similarity ratio involving the side \(PR\) and its corresponding side \(AC\):

\(\frac{PR}{AC} = \frac{1}{3}\)

Substitute the known length of \(AC = 15 \text{ cm}\):

\(\frac{PR}{15 \text{ cm}} = \frac{1}{3}\)

To find \(PR\), multiply both sides by \(15 \text{ cm}\):

\(PR = \frac{1}{3} \times 15 \text{ cm}\)

\(PR = 5 \text{ cm}\)

Thus, the length of side \(PR\) is \(5 \text{ cm}\).

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Similar Questions

  1. The areas of two similar triangles $\Delta$XYZ and $\Delta$LMN are 49 cm$^2$ and 9 cm$^2$, respectively. If LM = 9 cm, then the length of XY is:
  2. For a pair of similar triangles, the angles made at \(Q\) is same in both the triangles \(PQR\) and \(LQJ\).

    If the length of side \(QJ\) is 10 cm and \(QR\) is 5 cm, what is the ratio of their total areas?

  3. \(\Delta OPQ\) is similar to \(\Delta RST\). If the ratio of OP : RS is 3 : 5 and if PQ = 6 cm, then the length of ST is:
  4. Which of the following is the property of similar triangle?
  5. If in triangle \(\Delta\text{ABC}\) \(\text{AB}= 2\text{cm}\), \(\text{BC}=4\text{cm}\), and \(\text{AC}= 5\text{ cm}\) and in triangle \(\Delta\text{PQR}\) \(\text{PQ}= 12\text{cm}\), \(\text{QR}= 24\text{ cm}\), and \(\text{PR}=30\text{ cm}\), then triangles are:
  6. Two triangle are called similar if
  7. The areas of two similar triangles \(\Delta XYZ\) and \(\Delta LMN\) are \(49\ cm^2\) and \(9\ cm^2\), respectively. If LM = 9 cm, then the length of XY is:

Important Questions from Triangles, Congruence and Similarity

  1. G is the centroid of the equilateral triangle ABC. If AB = 8√ 3 cm, then the length of AG is equal to:

  2. If sides of a triangle are 12 cm, 15 cm and 21 cm, then what is the inradius (in cm) of the triangle?

  3. What is the area of quadrilateral ABCD?

  4. It is given that ΔABC ~ ΔXYZ and Area ΔABC : Area ΔXYZ = 81 : 25. If AB = 18 cm, BC = 10 cm, CA = 15 cm, then what is the side XZ (in cm)?

  5. Sides of two similar triangles are in the ratio 4 ∶ 9. Area of these triangles are in the ratio:

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