For a pair of similar triangles, the angles made at \(Q\) is same in both the triangles \(PQR\) and \(LQJ\).
If the length of side \(QJ\) is 10 cm and \(QR\) is 5 cm, what is the ratio of their total areas?
To find the ratio of the total areas of the similar triangles \(\triangle PQR\) and \(\triangle LQJ\), we can use the property of similar triangles that states the ratio of their areas is equal to the square of the ratio of their corresponding sides.
Given:
Since the triangles are similar, the ratio of corresponding sides is:
\(\frac{QJ}{QR} = \frac{10}{5} = 2\)
The ratio of the areas of two similar triangles is the square of the ratio of their corresponding sides:
\(\left(\frac{10}{5}\right)^2 = 2^2 = 4\)
Therefore, the ratio of the areas of \(\triangle LQJ\) to \(\triangle PQR\) is 4.
Hence, the correct answer is 4.
Triangles \(PQR\) and \(ABC\) are similar triangles. Triangle \(ABC\) have the following sides
\(AB = 12 \text{ cm}\),
\(AC = 15 \text{ cm}\),
\(CB = 21 \text{ cm}\).
Triangle \(PQR\) have the following sides:
\(PQ = 4 \text{ cm}\),
\(RQ = 7 \text{ cm}\).
What is the length of side \(PR\)?
In a $\Delta ABC$, $\angle C = (9/4) \angle B = (3/2) (\angle A+\angle B)$. Find the measure of the angles.
Triangles \(PQR\) and \(ABC\) are similar triangles. Triangle \(ABC\) have the following sides
\(AB = 12 \text{ cm}\),
\(AC = 15 \text{ cm}\),
\(CB = 21 \text{ cm}\).
Triangle \(PQR\) have the following sides:
\(PQ = 4 \text{ cm}\),
\(RQ = 7 \text{ cm}\).
What is the length of side \(PR\)?