The problem states that \(\Delta OPQ\) is similar to \(\Delta RST\). This means their corresponding sides are in the same ratio.
Since the triangles are similar, the ratio of sides PQ and ST must be equal to the ratio of sides OP and RS:
\(\frac{PQ}{ST} = \frac{OP}{RS}\)We are given:
Substitute the known values into the proportion:
\(\frac{6 \text{ cm}}{ST} = \frac{3}{5}\)To solve for ST, cross-multiply:
\(6 \text{ cm} \times 5 = 3 \times ST\) \(30 \text{ cm} = 3 \times ST\)Now, divide by 3 to find ST:
\(ST = \frac{30 \text{ cm}}{3}\) \(ST = 10 \text{ cm}\)Therefore, the length of ST is 10 cm.
Triangles \(PQR\) and \(ABC\) are similar triangles. Triangle \(ABC\) have the following sides
\(AB = 12 \text{ cm}\),
\(AC = 15 \text{ cm}\),
\(CB = 21 \text{ cm}\).
Triangle \(PQR\) have the following sides:
\(PQ = 4 \text{ cm}\),
\(RQ = 7 \text{ cm}\).
What is the length of side \(PR\)?
For a pair of similar triangles, the angles made at \(Q\) is same in both the triangles \(PQR\) and \(LQJ\).
If the length of side \(QJ\) is 10 cm and \(QR\) is 5 cm, what is the ratio of their total areas?
In a $\Delta ABC$, $\angle C = (9/4) \angle B = (3/2) (\angle A+\angle B)$. Find the measure of the angles.
Triangles \(PQR\) and \(ABC\) are similar triangles. Triangle \(ABC\) have the following sides
\(AB = 12 \text{ cm}\),
\(AC = 15 \text{ cm}\),
\(CB = 21 \text{ cm}\).
Triangle \(PQR\) have the following sides:
\(PQ = 4 \text{ cm}\),
\(RQ = 7 \text{ cm}\).
What is the length of side \(PR\)?
For a pair of similar triangles, the angles made at \(Q\) is same in both the triangles \(PQR\) and \(LQJ\).
If the length of side \(QJ\) is 10 cm and \(QR\) is 5 cm, what is the ratio of their total areas?