For two similar triangles, the ratio of their areas is equal to the square of the ratio of their corresponding sides.
Mathematically, if \(\Delta XYZ \sim \Delta LMN\), then:
\( \frac{\text{Area}(\Delta XYZ)}{\text{Area}(\Delta LMN)} = \left(\frac{XY}{LM}\right)^2 \)
Given:
\( \frac{49}{9} = \left(\frac{XY}{9}\right)^2 \)
\( \sqrt{\frac{49}{9}} = \frac{XY}{9} \)
\( \frac{7}{3} = \frac{XY}{9} \)
\( XY = \frac{7}{3} \times 9 \)
\( XY = 7 \times 3 \)
\( XY = 21\ cm \)
Therefore, the length of XY is 21 cm.
Triangles \(PQR\) and \(ABC\) are similar triangles. Triangle \(ABC\) have the following sides
\(AB = 12 \text{ cm}\),
\(AC = 15 \text{ cm}\),
\(CB = 21 \text{ cm}\).
Triangle \(PQR\) have the following sides:
\(PQ = 4 \text{ cm}\),
\(RQ = 7 \text{ cm}\).
What is the length of side \(PR\)?
For a pair of similar triangles, the angles made at \(Q\) is same in both the triangles \(PQR\) and \(LQJ\).
If the length of side \(QJ\) is 10 cm and \(QR\) is 5 cm, what is the ratio of their total areas?
In a $\Delta ABC$, $\angle C = (9/4) \angle B = (3/2) (\angle A+\angle B)$. Find the measure of the angles.
Triangles \(PQR\) and \(ABC\) are similar triangles. Triangle \(ABC\) have the following sides
\(AB = 12 \text{ cm}\),
\(AC = 15 \text{ cm}\),
\(CB = 21 \text{ cm}\).
Triangle \(PQR\) have the following sides:
\(PQ = 4 \text{ cm}\),
\(RQ = 7 \text{ cm}\).
What is the length of side \(PR\)?
For a pair of similar triangles, the angles made at \(Q\) is same in both the triangles \(PQR\) and \(LQJ\).
If the length of side \(QJ\) is 10 cm and \(QR\) is 5 cm, what is the ratio of their total areas?