The problem asks us to find the greatest number among three numbers that are in a specific ratio and have a given sum.
Let the three numbers be represented using the given ratio $11 : 16 : 23$. We can denote these numbers as $11x$, $16x$, and $23x$, where '$x$' is a common multiplier.
We are given that the sum of these three numbers is $150$. Therefore, we can set up the equation:
$11x + 16x + 23x = 150$
First, sum the coefficients of '$x$':
$ (11 + 16 + 23)x = 150 $
$ 50x = 150 $
Now, solve for '$x$' by dividing both sides by $50$:
$ x = \frac{150}{50} $
$ x = 3 $
The three numbers are $11x$, $16x$, and $23x$. The greatest number corresponds to the largest part of the ratio, which is $23$. To find the value of the greatest number, substitute the value of '$x$' ($x=3$) into the expression for the greatest number:
Greatest Number = $23x$
Greatest Number = $23 \times 3$
Greatest Number = $69$
Thus, the greatest number among the three is $69$.
In a mixture of 156 litres, the ratio of milk and water is 7 : 6. How much water should be added to make the ratio 14 : 13?
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The third proportional to 9 and 15 is:
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