The problem asks us to find the greatest number among three numbers that are in a specific ratio and have a given sum.
Let the three numbers be represented using the given ratio $11 : 16 : 23$. We can denote these numbers as $11x$, $16x$, and $23x$, where '$x$' is a common multiplier.
We are given that the sum of these three numbers is $150$. Therefore, we can set up the equation:
$11x + 16x + 23x = 150$
First, sum the coefficients of '$x$':
$ (11 + 16 + 23)x = 150 $
$ 50x = 150 $
Now, solve for '$x$' by dividing both sides by $50$:
$ x = \frac{150}{50} $
$ x = 3 $
The three numbers are $11x$, $16x$, and $23x$. The greatest number corresponds to the largest part of the ratio, which is $23$. To find the value of the greatest number, substitute the value of '$x$' ($x=3$) into the expression for the greatest number:
Greatest Number = $23x$
Greatest Number = $23 \times 3$
Greatest Number = $69$
Thus, the greatest number among the three is $69$.
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Atul purchased Bread costing Rs.20 and gave a 100 rupee note to the shopkeeper. The shopkeeper gave the balance money in coins of denomination Rs.2, Rs.5 and Rs.10. If these coins are in the ratio 5 ∶ 4 ∶ 1, then how many Rs.5 coins did the shopkeeper give?
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