The average age of 3 persons is 30 years.If their ages are in the ratio of 3 : 5 : 7 respectively, then the age of the eldest person is:
42 Years
The problem involves finding the age of the eldest person given the average age of three people and the ratio of their ages.
The average age of 3 persons is 30 years. The total age is calculated by multiplying the average age by the number of persons.
Total Age = Average Age $\times$ Number of Persons
Total Age = 30 years $\times$ 3 = 90 \text{ years}
The ages are in the ratio 3 : 5 : 7. Let the common multiplier be '$x$'. Therefore, the ages can be represented as $3x$, $5x$, and $7x$ years.
The sum of the individual ages must equal the total age calculated in Step 1.
Sum of Ages = $3x + 5x + 7x$
Set the sum equal to the total age:
$3x + 5x + 7x = 90$
$15x = 90$
Solve for '$x$':
$x = \frac{90}{15}
$x = 6$
The eldest person corresponds to the largest part of the ratio, which is $7x$. Substitute the value of '$x$' found in Step 3.
Eldest Person's Age = $7x$
Eldest Person's Age = $7 \times 6$
Eldest Person's Age = 42 \text{ years}
The third proportional to 9 and 15 is:
The income of A and B are in the ratio 5 : 3. The expenses of A, B and C are in the ratio of 8 : 5 : 2. If C spends 2000 and B saves ₹ 700, then A saves:
If A : B = 2 : 3, B : C = 3 : 4 and C : D = 3 : 5 then value of A : B : C : D is:
In a mixture of 156 litres, the ratio of milk and water is 7 : 6. How much water should be added to make the ratio 14 : 13?
If the ratio of the first to second number is 3 : 4 and that of the second to the third number is 8 : 5, and sum of three numbers is 190 then the third number is:
The third proportional to 9 and 15 is:
The income of A and B are in the ratio 5 : 3. The expenses of A, B and C are in the ratio of 8 : 5 : 2. If C spends 2000 and B saves ₹ 700, then A saves:
If A : B = 2 : 3, B : C = 3 : 4 and C : D = 3 : 5 then value of A : B : C : D is: