The average age of 3 persons is 30 years.If their ages are in the ratio of 3 : 5 : 7 respectively, then the age of the eldest person is:
42 Years
The problem involves finding the age of the eldest person given the average age of three people and the ratio of their ages.
The average age of 3 persons is 30 years. The total age is calculated by multiplying the average age by the number of persons.
Total Age = Average Age $\times$ Number of Persons
Total Age = 30 years $\times$ 3 = 90 \text{ years}
The ages are in the ratio 3 : 5 : 7. Let the common multiplier be '$x$'. Therefore, the ages can be represented as $3x$, $5x$, and $7x$ years.
The sum of the individual ages must equal the total age calculated in Step 1.
Sum of Ages = $3x + 5x + 7x$
Set the sum equal to the total age:
$3x + 5x + 7x = 90$
$15x = 90$
Solve for '$x$':
$x = \frac{90}{15}
$x = 6$
The eldest person corresponds to the largest part of the ratio, which is $7x$. Substitute the value of '$x$' found in Step 3.
Eldest Person's Age = $7x$
Eldest Person's Age = $7 \times 6$
Eldest Person's Age = 42 \text{ years}
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