The third proportional to 9 and 15 is:
25
To find the third proportional to two numbers, say a and b, we look for a number x such that the ratio a : b is the same as b : x. This can be written as:
$ a : b \:: b : x $
Or in fractional form:
$ \frac{a}{b} = \frac{b}{x} $
In this problem, we have a = 9 and b = 15. We need to find the third proportional, x.
Set up the proportion:
$ \frac{9}{15} = \frac{15}{x} $
To solve for x, we can cross-multiply:
$ 9 \times x = 15 \times 15 $
Calculate the product on the right side:
$ 9x = 225 $
Now, divide both sides by 9 to isolate x:
$ x = \frac{225}{9} $
$ x = 25 $
The third proportional to 9 and 15 is 25.
If \(\frac{a}{b} = \frac{7}{9}, \frac{b}{c} = \frac{3}{5}\) , then the value of a : b : c is
The average age of 3 persons is 30 years.If their ages are in the ratio of 3 : 5 : 7 respectively, then the age of the eldest person is:
The income of A and B are in the ratio 5 : 3. The expenses of A, B and C are in the ratio of 8 : 5 : 2. If C spends 2000 and B saves ₹ 700, then A saves:
If the ratio between two numbers are 3 : 4. If the first number and second number are increased by 40% and 50% respectively. Then the new ratio of the numbers are:
The cost of a diamond is directly proportional to the square of its weight. The cost of a 14 gm diamond is Rs. 2560. This diamond got broken down into two pieces in the ratio of 5 ∶ 9. How much loss percent is incurred due to this breakage ? (Correct to two decimal places)
Atul purchased Bread costing Rs.20 and gave a 100 rupee note to the shopkeeper. The shopkeeper gave the balance money in coins of denomination Rs.2, Rs.5 and Rs.10. If these coins are in the ratio 5 ∶ 4 ∶ 1, then how many Rs.5 coins did the shopkeeper give?
A person divides a certain amount among his three sons in the ratio of 3 ∶ 4 ∶ 5. If he had divided this amount in the ratio of 1/3,1/4,1/5, his son, who had got the lowest share earlier, would get Rs.1,188 more. Find the amount (in Rs).
In a school 3/8 of the number of students are girls and the rest are boys. One-third of the number of boys are below 10 years and 2/3 the number if girls are also below 10 years. If the number of students of age 10 or more years is 260. then the number of boys in the school is:
If a : b : c = \(\frac{1}{4} : \frac{1}{3} : \frac{1}{2}, \) then \( \ \frac{a}{b} : \frac{b}{c} : \frac{c}{a} = ?\)