All Exams Test series for 1 year @ ₹349 only
Question

In a mixture of 156 litres, the ratio of milk and water is 7 : 6. How much water should be added to make the ratio 14 : 13?

This question was previously asked in
RBI Assistant Prelims Memory Based Paper (27 March 2022) (Shift 2)
The correct answer is

6 litres

Solving the Milk-Water Mixture Ratio Problem

This problem involves calculating the amount of water to add to a milk and water mixture to change its ratio. We start with a total volume and an initial ratio, and we need to find how much water to add to achieve a new ratio.

Calculating Initial Quantities of Milk and Water

First, let's determine the initial amounts of milk and water in the 156-litre mixture. The ratio of milk to water is given as 7 : 6.

  • The total number of parts in the initial ratio is the sum of the ratio components: $7 + 6 = 13$ parts.
  • The total volume of the mixture is 156 litres. We can find the volume represented by one part by dividing the total volume by the total number of parts: $$ \text{Volume per part} = \frac{\text{Total Volume}}{\text{Total Parts}} = \frac{156 \text{ litres}}{13 \text{ parts}} = 12 \text{ litres/part} $$
  • Now, we calculate the initial quantity of milk and water:
    • Initial Milk = $7 \text{ parts} \times 12 \text{ litres/part} = 84 \text{ litres}$
    • Initial Water = $6 \text{ parts} \times 12 \text{ litres/part} = 72 \text{ litres}$

We can represent these initial quantities in a table:

Component Ratio Part Quantity (litres)
Milk 7 84
Water 6 72
Total 13 156

Determining the Amount of Water to Add

The goal is to change the ratio of milk to water to 14 : 13 by adding only water. The amount of milk remains constant.

  • Let the amount of water added be '$x$' litres.
  • The new quantity of milk will still be 84 litres.
  • The new quantity of water will be the initial quantity plus the added water: $72 + x$ litres.
  • The desired new ratio is Milk : Water = 14 : 13.
  • We can set up an equation using the new quantities and the desired ratio: $$ \frac{\text{New Milk Quantity}}{\text{New Water Quantity}} = \frac{14}{13} $$ $$ \frac{84}{72 + x} = \frac{14}{13} $$

Solving the Ratio Equation

To find the value of '$x$', we solve the equation derived above.

  • Cross-multiply the equation: $$ 84 \times 13 = 14 \times (72 + x) $$
  • Calculate the product on the left side: $$ 1092 = 14 \times (72 + x) $$
  • Distribute the 14 on the right side: $$ 1092 = (14 \times 72) + (14 \times x) $$ $$ 1092 = 1008 + 14x $$
  • Isolate the term with '$x$' by subtracting 1008 from both sides: $$ 1092 - 1008 = 14x $$ $$ 84 = 14x $$
  • Solve for '$x$' by dividing both sides by 14: $$ x = \frac{84}{14} $$ $$ x = 6 $$

So, 6 litres of water should be added.

Verification of the New Ratio

Let's check if adding 6 litres of water results in the desired 14 : 13 ratio.

  • New Milk Quantity = 84 litres.
  • New Water Quantity = Initial Water + Added Water = $72 + 6 = 78$ litres.
  • The new ratio is Milk : Water = 84 : 78.
  • Simplify the ratio by dividing both numbers by their greatest common divisor, which is 6: $$ \frac{84}{6} : \frac{78}{6} = 14 : 13 $$

The new ratio matches the target ratio of 14 : 13. Therefore, the amount of water to be added is indeed 6 litres.

Was this answer helpful?

Similar Questions

  1. If the ratio of the first to second number is 3 : 4 and that of the second to the third number is 8 : 5, and sum of three numbers is 190 then the third number is:


Important Questions from Ratio and Proportion

  1. The cost of a diamond is directly proportional to the square of its weight. The cost of a 14 gm diamond is Rs. 2560. This diamond got broken down into two pieces in the ratio of 5 ∶ 9. How much loss percent is incurred due to this breakage ? (Correct to two decimal places)

  2. Atul purchased Bread costing Rs.20 and gave a 100 rupee note to the shopkeeper. The shopkeeper gave the balance money in coins of denomination Rs.2, Rs.5 and Rs.10. If these coins are in the ratio 5 ∶ 4 ∶ 1, then how many Rs.5 coins did the shopkeeper give?

  3. A person divides a certain amount among his three sons in the ratio of 3 ∶ 4 ∶ 5. If he had divided this amount in the ratio of 1/3,1/4,1/5, his son, who had got the lowest share earlier, would get Rs.1,188 more. Find the amount (in Rs).

  4. In a school 3/8 of the number of students are girls and the rest are boys. One-third of the number of boys are below 10 years and 2/3 the number if girls are also below 10 years. If the number of students of age 10 or more years is 260. then the number of boys in the school is:

  5. If a : b : c = \(\frac{1}{4} : \frac{1}{3} : \frac{1}{2}, \)  then  \( \ \frac{a}{b} : \frac{b}{c} : \frac{c}{a} = ?\)

Need Expert Advice?
Upcoming Exams
RBI Grade B
July 25, 2026
SBI PO
August 01, 2026
IBPS PO
August 22, 2026
IBPS SO
August 29, 2026
IBPS Clerk
October 10, 2026
Test Series
RBI Assistant img
Banking
RBI Assistant (Pre & mains) 2026 Mock Test Series
190 Tests 1 Tests Free
4666 Attempts
4.7(27)
English, Hindi

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App