This question requires calculating the third proportional of two given numbers, 8 and 20.
If three numbers $a$, $b$, and $c$ are in continued proportion, then the ratio of the first to the second is equal to the ratio of the second to the third. This is written as:
$ a : b :: b : c $
This implies the relationship:
$ \frac{a}{b} = \frac{b}{c} $
In this relationship, $c$ is the third proportional to $a$ and $b$.
Given numbers are $a=8$ and $b=20$. We need to find the third proportional, $x$.
Setting up the proportion:
$ 8 : 20 :: 20 : x $
Using the cross-product rule (product of extremes equals product of means):
$ \frac{8}{20} = \frac{20}{x} $
Cross-multiplying gives:
$ 8 \times x = 20 \times 20 $
Calculate the product on the right side:
$ 8x = 400 $
To find the value of $x$, divide both sides by 8:
$ x = \frac{400}{8} $
$ x = 50 $
The value of x, which is the third proportional of 8 and 20, is 50.
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Atul purchased Bread costing Rs.20 and gave a 100 rupee note to the shopkeeper. The shopkeeper gave the balance money in coins of denomination Rs.2, Rs.5 and Rs.10. If these coins are in the ratio 5 ∶ 4 ∶ 1, then how many Rs.5 coins did the shopkeeper give?
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