The sides of a rectangular field are 77 m and 98 m long. Its area is equal to the area of a circular field. What is the perimeter (in m) of the circular field? (Take \(\pi = \frac{22}{7}\))
308
The area of the rectangular field is \(77 \times 98 = 7546 \text{ m}^2\).
This is equal to the area of the circular field, so \(\pi r^2 = 7546\).
Using \(\pi = \frac{22}{7}\): \(\frac{22}{7} \times r^2 = 7546 \Rightarrow r^2 = 2401 \Rightarrow r = 49 \text{ m}\).
The perimeter (circumference) of the circular field is \(2\pi r = 2 \times \frac{22}{7} \times 49 = 308 \text{ m}\).
Hence, the perimeter of the circular field is 308 m.
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Take $\pi = \frac{22}{7}$
