Let the sides of the rectangle be $3x$ and $4x$ since they are in the ratio 3:4.
The formula for the perimeter of a rectangle is $P = 2(l + w)$, where $l$ is the length and $w$ is the width.
Given the perimeter $P = 42$ cm:
$2(3x + 4x) = 42$
$2(7x) = 42$
$14x = 42$
Solving for $x$:
$x = \frac{42}{14} = 3$
Now, calculate the actual lengths of the sides:
The diagonal of a rectangle can be calculated using the Pythagorean theorem, where the diagonal ($d$) is the hypotenuse, and the sides ($l$ and $w$) are the other two sides of a right-angled triangle.
The formula is $d^2 = l^2 + w^2$.
Substitute the calculated side lengths:
$d^2 = (12 \text{ cm})^2 + (9 \text{ cm})^2$
$d^2 = 144 \text{ cm}^2 + 81 \text{ cm}^2$
$d^2 = 225 \text{ cm}^2$
Taking the square root to find the diagonal:
$d = \sqrt{225 \text{ cm}^2}$
$d = 15 \text{ cm}$
Therefore, the length of the diagonal is 15 cm.
The shorter side of a rectangle is 15 cm less than the longer side. The numerical value of its area is equal to 5 times the numerical value of its perimeter. What is the length (in cm) of its longer side?