(Use $\pi = \frac{22}{7}$)
The perimeter of a sector is calculated using the formula:
Perimeter = $2r + L$, where $r$ is the radius and $L$ is the arc length.
The arc length $L$ is given by:
$L = \frac{\theta}{360^\circ} \times 2\pi r$
Given:
Substitute the given values into the arc length formula:
$L = \frac{125^\circ}{360^\circ} \times 2 \times \frac{22}{7} \times 18\text{ cm}$
Simplify the expression:
$L = \frac{125}{360} \times \frac{44}{7} \times 18\text{ cm}$
$L = \frac{25}{72} \times \frac{44}{7} \times 18\text{ cm}$
$L = \frac{25}{4} \times \frac{44}{7}\text{ cm}$
$L = 25 \times \frac{11}{7}\text{ cm}$
$L = \frac{275}{7}\text{ cm}$
Approximately, $L \approx 39.29\text{ cm}$.
Now, calculate the total perimeter using the formula Perimeter = $2r + L$:
Perimeter = $2 \times 18\text{ cm} + \frac{275}{7}\text{ cm}$
Perimeter = $36\text{ cm} + \frac{275}{7}\text{ cm}$
Perimeter = $\frac{36 \times 7}{7}\text{ cm} + \frac{275}{7}\text{ cm}$
Perimeter = $\frac{252}{7}\text{ cm} + \frac{275}{7}\text{ cm}$
Perimeter = $\frac{527}{7}\text{ cm}$
Calculate the final approximate value:
Perimeter $\approx 75.2857\text{ cm}$
Rounding to one decimal place, the approximate perimeter is $75.3\text{ cm}$.
Calculate the area of the triangle whose sides are 8 cm, 9 cm and 13 cm. (Rounded up to two decimal places)