The initial length of the wire is determined by the circumference of the circle.
Given the radius $r = 56$ m.
The circumference formula is $C = 2 \pi r$. Using the approximation $\pi \approx \frac{22}{7}$:
$C = 2 \times \frac{22}{7} \times 56$
$C = 2 \times 22 \times 8$
$C = 352 \text{ m}$
The wire, after being cut, is bent into a square. Therefore, the perimeter of the square is equal to the wire's total length (the circle's circumference).
Let the side length of the square be $s$. The perimeter $P$ of the square is $P = 4s$.
$4s = 352 \text{ m}$
To find the side length $s$, divide the perimeter by 4:
$s = \frac{352}{4}$
$s = 88 \text{ m}$
The diagonal $d$ of a square can be calculated using the Pythagorean theorem or the formula $d = s\sqrt{2}$.
Substitute the side length $s = 88$ m into the formula:
$d = 88\sqrt{2} \text{ m}$
Thus, the measure of the diagonal of the square is $88\sqrt{2}$ m.
The shorter side of a rectangle is 15 cm less than the longer side. The numerical value of its area is equal to 5 times the numerical value of its perimeter. What is the length (in cm) of its longer side?