This problem requires finding an initial sum of money based on initial and final ratios after a transfer.
Let the initial amounts Arun and Ahaan had be $9x$ and $5x$, representing the $9:5$ ratio.
When Arun gives ₹12 to Ahaan:
The new ratio is $4:3$. This gives the equation:
$ \frac{9x - 12}{5x + 12} = \frac{4}{3} $
Cross-multiply to solve the equation:
$ 3(9x - 12) = 4(5x + 12) $
$ 27x - 36 = 20x + 48 $
Group terms with $x$ and constants:
$ 27x - 20x = 48 + 36 $
$ 7x = 84 $
Calculate $x$:
$ x = \frac{84}{7} = 12 $
Arun's initial amount was $9x$. Substitute the value of $x$:
Initial Amount = $9 \times 12$
$ 9 \times 12 = 108 $
Arun initially had ₹108.
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Atul purchased Bread costing Rs.20 and gave a 100 rupee note to the shopkeeper. The shopkeeper gave the balance money in coins of denomination Rs.2, Rs.5 and Rs.10. If these coins are in the ratio 5 ∶ 4 ∶ 1, then how many Rs.5 coins did the shopkeeper give?
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If a : b : c = \(\frac{1}{4} : \frac{1}{3} : \frac{1}{2}, \) then \( \ \frac{a}{b} : \frac{b}{c} : \frac{c}{a} = ?\)