Solving Rectangular Field Perimeter
We are given a rectangular field where the ratio of its length to its breadth is $7:6$. We are also told that the breadth is $35\text{ m}$ less than the length.
Calculating Dimensions
Let the length of the field be $L$ and the breadth be $B$. According to the given ratio:
- $L = 7x$
- $B = 6x$
The difference between the length and breadth is $35\text{ m}$:
$L - B = 35$
Substitute the expressions for $L$ and $B$ in terms of $x$:
$7x - 6x = 35$
Solving for $x$:
$x = 35$
Now, we can find the actual length and breadth:
- Length $L = 7x = 7 \times 35 = 245\text{ m}$
- Breadth $B = 6x = 6 \times 35 = 210\text{ m}$
Calculating Perimeter
The formula for the perimeter of a rectangle is $P = 2(L+B)$.
Substitute the calculated values of $L$ and $B$:
$P = 2(245\text{ m} + 210\text{ m})$
$P = 2(455\text{ m})$
$P = 910\text{ m}$
Therefore, the perimeter of the rectangular field is $910\text{ m}$.
Similar Questions
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Important Questions from 2-D Mensuration
- The sides of a rectangular field are 169 m and 154 m long. Its area is equal to the area of a circular field. What is the circumference (in m) of the circular field? Take $\pi = \frac{22}{7}$
- Find the area of a sector with a central angle of 150° in a circle with a radius of 12 cm.
- The area of a square is $2304$ cm$^2$. Its perimeter is equal to the perimeter of a regular hexagon. What is the area (in cm$^2$) of the hexagon?
Calculate the area of the triangle whose sides are 8 cm, 9 cm and 13 cm. (Rounded up to two decimal places)
- The length of a rectangular pitch is 30 m more than its breadth. Its area is $18,271$ m$^{2}$. Its breadth (in m) is:
