This is a simple interest problem. We need to find the rate of interest at which a principal amount doubles in 16 2/3 years.
Step 1: Understand the Formula
The formula for simple interest is: Simple Interest (SI) = (P × R × T) / 100
Where:
Step 2: Set up the Equation
Since the money doubles, the Simple Interest (SI) will be equal to the Principal (P). The time is given as 16 2/3 years, which is equal to 50/3 years.
Therefore, we can write the equation as:
P = (P × R × (50/3)) / 100
Step 3: Solve for R
We can simplify the equation by cancelling out 'P' from both sides:
1 = (R × (50/3)) / 100
Now, solve for R:
100 = R × (50/3)
R = (100 × 3) / 50
R = 6
Step 4: State the Answer
Therefore, the rate of simple interest is 6% per annum.
Step 5: Eliminate Incorrect Options
\(27^3 + 10^3 - 29^3 + 246\) is equal to:
What is the result of \(\dfrac{0.5^3 + 0.1^3 - 0.6^3}{3 \times 0.5 \times 0.1 \times 0.6}\)?
If \(x+\dfrac{1}{x}=2\sqrt{3}\), then find the value of \(x^3+\dfrac{1}{x^3}\).
Simplify.
\(\frac{2.5 \times 2.5 \times 2.5-1.5 \times 1.5 \times 1.5}{2.5 \times 2.5+2.5 \times 1.5+1.5 \times 1.5}\)
If \(2x + { {1} \over 3x}= 5, x ≠ 0\) , then what is the value of \(27x^3+{{1} \over 8x^3}\) ?
If x 2 + 4y 2 = 40, xy = 6 and x > 2y then the value of x - 2y is: