Simplify. \(\frac{2.5 \times 2.5 \times 2.5-1.5 \times 1.5 \times 1.5}{2.5 \times 2.5+2.5 \times 1.5+1.5 \times 1.5}\)
1
The question asks us to simplify the following mathematical expression:
$$ \frac{2.5 \times 2.5 \times 2.5 - 1.5 \times 1.5 \times 1.5}{2.5 \times 2.5 + 2.5 \times 1.5 + 1.5 \times 1.5} $$
This expression can be written more compactly using exponents:
$$ \frac{2.5^3 - 1.5^3}{2.5^2 + (2.5 \times 1.5) + 1.5^2} $$
To simplify this fraction, we can recognise that it fits a standard algebraic identity. The identity for the difference of two cubes is:
$$ a^3 - b^3 = (a - b)(a^2 + ab + b^2) $$
Let's compare this identity to our given expression. We can identify:
If we substitute these values into the identity, we get:
$$ (2.5)^3 - (1.5)^3 = (2.5 - 1.5)((2.5)^2 + (2.5 \times 1.5) + (1.5)^2) $$
Our original expression is the fraction \( \frac{2.5^3 - 1.5^3}{2.5^2 + (2.5 \times 1.5) + 1.5^2} \). Using our variables \(a\) and \(b\), this can be written as:
$$ \text{Expression} = \frac{a^3 - b^3}{a^2 + ab + b^2} $$
Now, we can substitute the factored form of \( a^3 - b^3 \) from the identity into our expression:
$$ \text{Expression} = \frac{(a - b)(a^2 + ab + b^2)}{a^2 + ab + b^2} $$
We can see that the term \( (a^2 + ab + b^2) \) exists in both the numerator and the denominator. Since \( a = 2.5 \) and \( b = 1.5 \), both are positive numbers. This means \( a^2 + ab + b^2 \) will be a positive value and certainly not zero. Therefore, we can safely cancel out this common factor:
$$ \text{Expression} = a - b $$
The expression simplifies to \( a - b \). Now, we substitute the values of \(a\) and \(b\) back into this simplified form:
$$ \text{Result} = 2.5 - 1.5 $$
Performing the subtraction:
$$ \text{Result} = 1 $$
So, the simplified value of the given expression is 1.
The final calculated result is 1. Let's check this against the provided options:
Our calculation confirms that Option 3 is the correct answer.
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