\(\dfrac{(5.17-2.19)^2-(5.17+2.19)^2}{11.3223}\)
-4
The given mathematical expression is:
\(\dfrac{(5.17-2.19)^2-(5.17+2.19)^2}{11.3223}\)
Let's denote \(a = 5.17\) and \(b = 2.19\). The expression can be written in the form:
\(\dfrac{(a-b)^2 - (a+b)^2}{c}\)
where \(c = 11.3223\).
We can simplify the numerator using algebraic identities. Recall the identities:
Now, let's subtract \((a+b)^2\) from \((a-b)^2\):
\((a-b)^2 - (a+b)^2 = (a^2 - 2ab + b^2) - (a^2 + 2ab + b^2)\)
Distribute the minus sign:
\(= a^2 - 2ab + b^2 - a^2 - 2ab - b^2\)
Group like terms:
\(= (a^2 - a^2) + (b^2 - b^2) + (-2ab - 2ab)\)
\(= 0 + 0 - 4ab\)
\(= -4ab\)
Now substitute the simplified numerator back into the original expression:
\(\dfrac{-4ab}{c}\)
Substitute the values \(a = 5.17\), \(b = 2.19\), and \(c = 11.3223\):
\(\dfrac{-4 \times 5.17 \times 2.19}{11.3223}\)
Let's calculate the product \(a \times b = 5.17 \times 2.19\):
5.17
x 2.19
------
4653 (5.17 x 0.09)
5170 (5.17 x 0.10)
103400 (5.17 x 2.00)
------
11.3223 (Summing the results, keeping track of decimal places)
So, \(5.17 \times 2.19 = 11.3223\).
Now substitute the product \(ab\) back into the expression:
\(\dfrac{-4 \times 11.3223}{11.3223}\)
The term \(11.3223\) appears in both the numerator and the denominator. Assuming \(11.3223 \neq 0\), we can cancel it out:
\(= -4\)
The value of the expression \(\dfrac{(5.17-2.19)^2-(5.17+2.19)^2}{11.3223}\) is \(-4\).
| Identity | Formula |
|---|---|
| Square of a Sum | \((a+b)^2 = a^2 + 2ab + b^2\) |
| Square of a Difference | \((a-b)^2 = a^2 - 2ab + b^2\) |
| Difference of Squares | \(a^2 - b^2 = (a-b)(a+b)\) |
| Sum of Cubes | \(a^3 + b^3 = (a+b)(a^2 - ab + b^2)\) |
| Difference of Cubes | \(a^3 - b^3 = (a-b)(a^2 + ab + b^2)\) |
Simplifying mathematical expressions involves rewriting them in a simpler, more understandable form. This often uses algebraic identities, factorization, combining like terms, and applying the order of operations (PEMDAS/BODMAS).
Understanding algebraic identities is a fundamental skill for simplifying complex expressions efficiently.
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