\(\dfrac{(0.73)^3+(0.31)^3}{(0.73)^2-0.73\times0.31+(0.31)^2}\)
1.04
The problem asks us to evaluate a given algebraic expression. The expression looks complex, but we can simplify it by recognizing a common algebraic identity.
The given expression is:
\(\dfrac{(0.73)^3+(0.31)^3}{(0.73)^2-0.73\times0.31+(0.31)^2}\)
Let's look at the structure of the expression. It is in the form of a fraction where the numerator is a sum of cubes and the denominator is a quadratic expression involving the same terms.
Consider the algebraic identity for the sum of cubes:
\(a^3 + b^3 = (a+b)(a^2 - ab + b^2)\)
Now, let's compare this identity with our given expression.
Let \(a = 0.73\) and \(b = 0.31\).
The numerator of the given expression is \((0.73)^3 + (0.31)^3\), which is in the form \(a^3 + b^3\).
The denominator of the given expression is \((0.73)^2 - 0.73 \times 0.31 + (0.31)^2\), which is in the form \(a^2 - ab + b^2\).
So, the given expression can be written as:
\(\dfrac{a^3 + b^3}{a^2 - ab + b^2}\)
Using the identity \(a^3 + b^3 = (a+b)(a^2 - ab + b^2)\), we can rewrite the numerator:
\(\dfrac{(a+b)(a^2 - ab + b^2)}{a^2 - ab + b^2}\)
Assuming that the denominator \(a^2 - ab + b^2\) is not equal to zero, we can cancel out the common term \((a^2 - ab + b^2)\) from the numerator and the denominator.
In this case, \(a=0.73\) and \(b=0.31\). The denominator is \((0.73)^2 - (0.73)(0.31) + (0.31)^2\). Since \(a\) and \(b\) are positive, \(a^2\) and \(b^2\) are positive. While \(ab\) is positive, the entire expression \(a^2 - ab + b^2\) for real numbers \(a, b\) is always non-negative (it is equal to \((a - b/2)^2 + 3b^2/4\)). If \(a=b=0\), it is zero, but here \(a\) and \(b\) are non-zero. If \(a\) and \(b\) have the same sign, it is zero only if \(a=b=0\). If \(a\) and \(b\) have opposite signs, it is always positive. Here \(a=0.73\) and \(b=0.31\) are positive, so \(a^2 - ab + b^2 > 0\).
Therefore, we can safely cancel the term:
\(\dfrac{(a+b)\cancel{(a^2 - ab + b^2)}}{\cancel{a^2 - ab + b^2}}\)
The simplified expression is simply:
\(a+b\)
Now, substitute the values of \(a\) and \(b\) back into the simplified expression:
\(a+b = 0.73 + 0.31\)
Adding these two numbers:
\(0.73 + 0.31 = 1.04\)
Thus, the value of the given algebraic expression is \(1.04\).
| Mathematical Concept | Application in Problem |
|---|---|
| Algebraic Identity \(a^3+b^3\) | Used to simplify the numerator. |
| Substitution | Assigning variables \(a\) and \(b\) to the numbers. |
| Fraction Simplification | Canceling common terms in numerator and denominator. |
| Addition of Decimals | Final calculation step. |
| Identity | Formula | Example Use |
|---|---|---|
| Sum of Cubes | \(a^3 + b^3 = (a+b)(a^2 - ab + b^2)\) | Used in this problem for the numerator. |
| Difference of Cubes | \(a^3 - b^3 = (a-b)(a^2 + ab + b^2)\) | Useful for expressions like \(\dfrac{a^3-b^3}{a^2+ab+b^2}\). |
| Square of Sum | \((a+b)^2 = a^2 + 2ab + b^2\) | Expanding terms like \((x+y)^2\). |
| Square of Difference | \((a-b)^2 = a^2 - 2ab + b^2\) | Expanding terms like \((x-y)^2\). |
| Difference of Squares | \(a^2 - b^2 = (a+b)(a-b)\) | Factoring terms like \(x^2 - 9\). |
Algebraic identities are fundamental equations that are true for all values of the variables involved. They are powerful tools used to simplify expressions, factor polynomials, and solve equations more efficiently.
Mastering these basic identities is crucial for anyone studying algebra or preparing for competitive exams that involve quantitative aptitude sections.
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