\(27^3 + 10^3 - 29^3 + 246\) is equal to:
-3460
Step 1 – compute each cube:
\(27^3 = 19{,}683\)
\(10^3 = 1{,}000\)
\(29^3 = 24{,}389\)
Step 2 – combine:
\(27^3 + 10^3 - 29^3 = 19{,}683 + 1{,}000 - 24{,}389 = 20{,}683 - 24{,}389 = -3{,}706\)
Step 3 – add 246:
\(-3{,}706 + 246 = -3{,}460\)
Hence the answer is −3,460.
What is the result of \(\dfrac{0.5^3 + 0.1^3 - 0.6^3}{3 \times 0.5 \times 0.1 \times 0.6}\)?
If \(x+\dfrac{1}{x}=2\sqrt{3}\), then find the value of \(x^3+\dfrac{1}{x^3}\).
Simplify.
\(\frac{2.5 \times 2.5 \times 2.5-1.5 \times 1.5 \times 1.5}{2.5 \times 2.5+2.5 \times 1.5+1.5 \times 1.5}\)
If \(2x + { {1} \over 3x}= 5, x ≠ 0\) , then what is the value of \(27x^3+{{1} \over 8x^3}\) ?
If x 2 + 4y 2 = 40, xy = 6 and x > 2y then the value of x - 2y is: