\(27^3 + 10^3 - 29^3 + 246\) is equal to:
-3460
Step 1 – compute each cube:
\(27^3 = 19{,}683\)
\(10^3 = 1{,}000\)
\(29^3 = 24{,}389\)
Step 2 – combine:
\(27^3 + 10^3 - 29^3 = 19{,}683 + 1{,}000 - 24{,}389 = 20{,}683 - 24{,}389 = -3{,}706\)
Step 3 – add 246:
\(-3{,}706 + 246 = -3{,}460\)
Hence the answer is −3,460.
Similar Questions
What is the result of \(\dfrac{0.5^3 + 0.1^3 - 0.6^3}{3 \times 0.5 \times 0.1 \times 0.6}\)?
- Given, $x = \sqrt{3}$, what is $(x + 1)^2 + (x - 1)^2$?
- The rate of simple interest per annum at which a sum of money double itself in 16 2/3 yrs. is
If \(x+\dfrac{1}{x}=2\sqrt{3}\), then find the value of \(x^3+\dfrac{1}{x^3}\).
Important Questions from Identities
If x 2 + 4y 2 = 40, xy = 6 and x > 2y then the value of x - 2y is:
- \(\dfrac{(5.17-2.19)^2-(5.17+2.19)^2}{11.3223}\)
If a(a + b + c) 2= 1792; b(a + b + c) 2= 1536; c(a + b + c) 2= 768 then what will be the value of a?
If a + b + c = 5, a 2+ b 2+ c 2= 27, a 3 + b 3 + c 3 = 125, then the value of \(\frac{abc}{5}\) is:
(999) 2- 2 2=
