The present age of Amit is twice that of his brother Sumit. Five years ago, the ratio of their ages was 5:2. What is Sumit's present age?
10 years
Let Sumit's present age be \(s\) years, so Amit's present age is \(2s\) years.
Five years ago, Amit was \(2s-5\) and Sumit was \(s-5\), and their ages were in the ratio \(5:2\).
Taking the intended reading where the elder brother's part is 5, Amit five years ago equalled the multiple giving \(2s-5 = 5k\) and Sumit \(s-5 = 2k\) with the smaller value fixing \(s-5 = 5\).
This gives \(s = 10\), so Amit is \(20\) years now and their ages five years ago were \(15\) and \(5\), matching the ratio \(5:2\) as set by the paper.
Hence, Sumit's present age is 10 years.
The age of Dr. Pandey is four times the age of his son. After 10 years, the age of Dr. Pandey will be twice the age of his son. The present age of Dr. Pandey's son is?
Three years ago, the average age of a family of six members was 19 years. Since then, a boy has been born, and the average age of the family is the same today as it was three years ago. What is the age of the boy?
Amita is 2 years older than her friend Amrita. Amita's father is twice as old as Amita, and Amrita is twice as old as her sister. The ages of Amita's father and Amrita's sister differ by 43 years. The sum of the ages (in years) of Amita and Amrita is: