To find the length of the diagonal of a rectangle, we can use the Pythagorean theorem. The theorem states that in a right-angled triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides. In a rectangle, the length, width, and diagonal form a right-angled triangle.
Let the length of the rectangle be '$l$' and the width be '$w$'. Let the diagonal be '$d$'. According to the Pythagorean theorem:
$d^2 = l^2 + w^2$
Given:
Substitute the values into the formula:
$d^2 = 9^2 + 5^2$
$d^2 = 81 + 25$
$d^2 = 106$
To find the diagonal '$d$', take the square root of both sides:
$d = \sqrt{106}$
Since length must be a positive value, we only consider the positive square root.
The length of the diagonal is $\sqrt{106}$ cm.
The shorter side of a rectangle is 15 cm less than the longer side. The numerical value of its area is equal to 5 times the numerical value of its perimeter. What is the length (in cm) of its longer side?