The ages of two siblings add up to 44 years. If one sibling is 4 years younger than twice the other's age, what is the difference between their ages?
12 years
Let the two ages be \(x\) and \(y\), with \(x + y = 44\).
One sibling is 4 years younger than twice the other, so \(y = 2x - 4\).
Substitute: \(x + (2x - 4) = 44 \Rightarrow 3x = 48 \Rightarrow x = 16\).
Then \(y = 44 - 16 = 28\).
Difference \(= 28 - 16 = 12\) years.
Hence, the difference between their ages is 12 years.
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