Tapan, Ravi, and Trisha shared a cake. Tapan had 1/4 of it, Trisha had 2/3 of it and Ravi had the rest. What was Ravi’s share of the cake?
1/12
The problem describes how a cake was shared among three people: Tapan, Ravi, and Trisha. We are given the fractions of the cake that Tapan and Trisha received. Our goal is to find the fraction of the cake that Ravi received, which is the remaining portion.
First, let's find the total fraction of the cake shared by Tapan and Trisha. Tapan had $\frac{1}{4}$ of the cake, and Trisha had $\frac{2}{3}$ of the cake. To find their combined share, we add these two fractions:
Total shared = Tapan's share + Trisha's share
Total shared = $\frac{1}{4} + \frac{2}{3}$
To add fractions, we need a common denominator. The least common multiple (LCM) of 4 and 3 is 12. We convert each fraction to have a denominator of 12:
Now, add the converted fractions:
Total shared = $\frac{3}{12} + \frac{8}{12} = \frac{3 + 8}{12} = \frac{11}{12}$
So, Tapan and Trisha together shared $\frac{11}{12}$ of the cake.
The entire cake represents the whole, which is 1. Since Tapan and Trisha took $\frac{11}{12}$ of the cake, Ravi received the rest. To find Ravi's share, we subtract the total shared amount from the whole cake (1).
Ravi's share = Whole cake - Total shared
Ravi's share = $1 - \frac{11}{12}$
We can write 1 as a fraction with the same denominator, 12: $1 = \frac{12}{12}$.
Ravi's share = $\frac{12}{12} - \frac{11}{12} = \frac{12 - 11}{12} = \frac{1}{12}$
Therefore, Ravi's share of the cake was $\frac{1}{12}$.
This matches option 1.
| Person | Share (Fraction) |
|---|---|
| Tapan | $\frac{1}{4}$ |
| Trisha | $\frac{2}{3}$ |
| Total Shared (Tapan + Trisha) | $\frac{11}{12}$ |
| Ravi | $\frac{1}{12}$ |
This problem involved adding and subtracting fractions. Here's a quick reminder:
Which fraction among the following is the least ?
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\(\frac{{3 \div 1 \times 2 + 5 - 2}}{{3 \times 3 - 2}}\)
Simplify the expression 441 ÷ \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)
If the sum of two positive numbers is 65 and the square root of their product is 26, then the sum of their reciprocals is:
The value of \(9 \div [\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{6}\div(\frac{3}{4}-\frac{1}{3})\;of\;\frac{2}{9}]\) is: