Select the option that can replace the question mark (?) in the following equation. 2 + 5 ÷ [5 + 8 ÷ \(\left(1+\frac{1}{3}\right)\) - 1 ] = ?
To solve the given mathematical expression, we need to follow the order of operations. A common acronym used for remembering the order is BODMAS or PEMDAS.
The expression is: \(2 + 5 \div [5 + 8 \div\left(1+\frac{1}{3}\right) - 1 ]\)
Let's break down the calculation according to the order of operations.
First, calculate the sum inside the small brackets:
\(1 + \frac{1}{3} = \frac{3}{3} + \frac{1}{3} = \frac{3+1}{3} = \frac{4}{3}\)
The expression now becomes:
\(2 + 5 \div [5 + 8 \div \left(\frac{4}{3}\right) - 1 ]\)
Next, perform the division inside the square brackets:
\(8 \div \left(\frac{4}{3}\right) = 8 \times \frac{3}{4}\)
Multiply 8 by the reciprocal of \(\frac{4}{3}\):
\(8 \times \frac{3}{4} = \frac{8 \times 3}{4} = \frac{24}{4} = 6\)
The expression now becomes:
\(2 + 5 \div [5 + 6 - 1 ]\)
Perform the addition and subtraction from left to right inside the square brackets:
\(5 + 6 - 1 = 11 - 1 = 10\)
The expression now becomes:
\(2 + 5 \div [10]\)
or simply
\(2 + 5 \div 10\)
Now, perform the division:
\(5 \div 10 = \frac{5}{10} = \frac{1}{2}\)
The expression now becomes:
\(2 + \frac{1}{2}\)
Finally, add the numbers:
\(2 + \frac{1}{2} = \frac{4}{2} + \frac{1}{2} = \frac{4+1}{2} = \frac{5}{2}\)
The value of the expression is \(\frac{5}{2}\).
| Step | Operation | Calculation | Expression Becomes |
|---|---|---|---|
| 1 | Innermost Parentheses | \(1+\frac{1}{3} = \frac{4}{3}\) | \(2 + 5 \div [5 + 8 \div \frac{4}{3} - 1 ]\) |
| 2 | Division inside Brackets | \(8 \div \frac{4}{3} = 6\) | \(2 + 5 \div [5 + 6 - 1 ]\) |
| 3 | Brackets Operations | \(5 + 6 - 1 = 10\) | \(2 + 5 \div 10\) |
| 4 | Division | \(5 \div 10 = \frac{1}{2}\) | \(2 + \frac{1}{2}\) |
| 5 | Addition | \(2 + \frac{1}{2} = \frac{5}{2}\) | \(\frac{5}{2}\) |
Thus, the result of the expression is \(\frac{5}{2}\).
| Order | Operation Type | Notes |
|---|---|---|
| 1st | Parentheses / Brackets | Work from innermost to outermost. |
| 2nd | Exponents / Orders | Calculate powers and roots. |
| 3rd | Multiplication and Division | Perform from left to right. |
| 4th | Addition and Subtraction | Perform from left to right. |
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