Let Narendra's present age be represented by $N$ and his mother's present age by $M$.
From the first statement, "Narendra's mother is four times as old as Narendra", we get the equation:
$ M = 4N \quad (1) $
From the second statement, "Four years ago, his mother was six times as old as Narendra was", we consider their ages four years ago:
This gives us the second equation:
$ M - 4 = 6(N - 4) \quad (2) $
Substitute the value of $M$ from equation (1) into equation (2):
$ 4N - 4 = 6(N - 4) $
Distribute the 6 on the right side:
$ 4N - 4 = 6N - 24 $
Rearrange the terms to solve for $N$:
$ 24 - 4 = 6N - 4N $
$ 20 = 2N $
$ N = \frac{20}{2} $
$ N = 10 $
Now, find the mother's age $M$ using equation (1):
$ M = 4N = 4 \times 10 $
$ M = 40 $
Check if the ages satisfy the conditions:
Both conditions are met.
Narendra's present age is 10 years and his mother's present age is 40 years.
The age of Dr. Pandey is four times the age of his son. After 10 years, the age of Dr. Pandey will be twice the age of his son. The present age of Dr. Pandey's son is?
Three years ago, the average age of a family of six members was 19 years. Since then, a boy has been born, and the average age of the family is the same today as it was three years ago. What is the age of the boy?
Amita is 2 years older than her friend Amrita. Amita's father is twice as old as Amita, and Amrita is twice as old as her sister. The ages of Amita's father and Amrita's sister differ by 43 years. The sum of the ages (in years) of Amita and Amrita is: