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Question

Manish fixed 48 poles in order to fence a square. If the distance between 2 poles is 5 m, then what will be the area of the square, formed?

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
$3600 \text{ m}^2$

Calculating the Square's Area Using Pole Information

The problem asks for the area of a square fence constructed using 48 poles, with each pole spaced 5 meters apart.

Perimeter Calculation

For a closed shape like a square, the number of intervals between poles is equal to the number of poles. Therefore, 48 poles create 48 intervals along the perimeter.

  • Number of poles = 48
  • Distance between poles = 5 m
  • Number of intervals = 48
  • Perimeter = Number of intervals $\times$ Distance between poles
  • Perimeter = $48 \times 5 \text{ m} = 240 \text{ m}$

Side Length Determination

A square has four equal sides. The perimeter is the total length of all sides.

  • Perimeter of a square = $4 \times \text{side length}$
  • $240 \text{ m} = 4 \times \text{side length}$
  • Side length = $\frac{240 \text{ m}}{4} = 60 \text{ m}$

Area Calculation

The area of a square is calculated by squaring its side length.

  • Area = $(\text{side length})^2$
  • Area = $(60 \text{ m})^2$
  • Area = $3600 \text{ m}^2$

The area of the square formed is $3600 \text{ m}^2$. This corresponds to Option B.

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