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Question

Loop 1 : MOV A, P1

MOV P2, A

JNB P3.3, Loop1

The program does the following

This question was previously asked in
UGC NET 2023 Electronic Science Question Paper (13-Dec-2023) (Shift 1)
The correct answer is

Read data from port 1 and write it to port 2 until bit 3 of port 3 is reset

To solve this problem, we need to understand the assembly program provided and determine what operation it performs based on the given instructions.

  1. Instruction Analysis:
    • MOV A, P1: This instruction moves the data from Port 1 to the accumulator (A). In essence, it reads data from Port 1.
    • MOV P2, A: This instruction writes the data from the accumulator (A) to Port 2. This means the data initially read from Port 1 is being moved to Port 2.
    • JNB P3.3, Loop1: This is a conditional jump instruction. It stands for "Jump if Not Bit" and checks bit 3 of Port 3. If this bit is not set (i.e., it is 0), the program jumps back to Loop1 to repeat the process. If bit 3 of Port 3 is set (i.e., it is 1), the program will not jump, and thus the loop will terminate.
  2. Logical Conclusion:
    • The loop continues to read data from Port 1 and write it to Port 2 as long as bit 3 of Port 3 is not set (i.e., while it is reset).
    • Once bit 3 of Port 3 becomes set, the loop terminates, stopping the data transfer between Port 1 and Port 2.

Based on the above analysis, the correct description of the program operation is: "Read data from port 1 and write it to port 2 until bit 3 of port 3 is reset."

Therefore, the correct answer is the option that states Read data from port 1 and write it to port 2 until bit 3 of port 3 is reset.

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Similar Questions

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    $D_7$$D_6$$D_5$$D_4$$D_3$$D_2$$D_1$$D_0$

    In 8255 programmable peripheral interface device, if the port A and port B are to be set in a hand shake mode along with port C, what are the bits in the 8 bit control word  to be set as 0 1 0.

  2. The number system for the machine code of the microprocessor 8085 is

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Important Questions from Microprocessors

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