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Question

The magnetic vector potential of an electromagnetic system is given by $  \vec{A}=(y \cos ax)  \vec{a_x} + (y+e^x)   \vec{a_z}$. The magnitude of the magnetic flux density at the origin is

The correct answer is

$\sqrt{2}$ Wb/m$^2$

Deriving Magnetic Flux Density from Vector Potential

The magnetic flux density, denoted by $\vec{B}$, is related to the magnetic vector potential, $\vec{A}$, through the curl operation. The fundamental relationship is given by:

$ \vec{B} = \nabla \times \vec{A} $

In Cartesian coordinates, the curl operator $\nabla \times$ is defined as:

$ \nabla \times \vec{A} = \begin{vmatrix} \vec{a_x} & \vec{a_y} & \vec{a_z} \\ \frac{\partial}{\partial x} & \frac{\partial}{\partial y} & \frac{\partial}{\partial z} \\ A_x & A_y & A_z \end{vmatrix} $

Calculating the Magnetic Flux Density ($\vec{B}$)

The given magnetic vector potential is:

$ \vec{A} = (y \cos ax) \vec{a_x} + 0 \vec{a_y} + (y+e^x) \vec{a_z} $

From this, we identify the components:

  • $ A_x = y \cos(ax) $
  • $ A_y = 0 $
  • $ A_z = y + e^x $

Now, let's calculate the necessary partial derivatives:

  • $ \frac{\partial A_z}{\partial y} = \frac{\partial}{\partial y}(y + e^x) = 1 $
  • $ \frac{\partial A_y}{\partial z} = \frac{\partial}{\partial z}(0) = 0 $
  • $ \frac{\partial A_x}{\partial z} = \frac{\partial}{\partial z}(y \cos ax) = 0 $
  • $ \frac{\partial A_z}{\partial x} = \frac{\partial}{\partial x}(y + e^x) = e^x $
  • $ \frac{\partial A_y}{\partial x} = \frac{\partial}{\partial x}(0) = 0 $
  • $ \frac{\partial A_x}{\partial y} = \frac{\partial}{\partial y}(y \cos ax) = \cos ax $

Substitute these into the curl formula:

$ \vec{B} = \left( \frac{\partial A_z}{\partial y} - \frac{\partial A_y}{\partial z} \right) \vec{a_x} + \left( \frac{\partial A_x}{\partial z} - \frac{\partial A_z}{\partial x} \right) \vec{a_y} + \left( \frac{\partial A_y}{\partial x} - \frac{\partial A_x}{\partial y} \right) \vec{a_z} $

$ \vec{B} = (1 - 0) \vec{a_x} + (0 - e^x) \vec{a_y} + (0 - \cos ax) \vec{a_z} $

$ \vec{B} = 1 \vec{a_x} - e^x \vec{a_y} - \cos(ax) \vec{a_z} $

Evaluating $\vec{B}$ at the Origin

The origin is the point where $ x=0 $, $ y=0 $, and $ z=0 $. We substitute these values into the expression for $\vec{B}$:

  • $ B_x = 1 $
  • $ B_y = -e^0 = -1 $
  • $ B_z = -\cos(a \cdot 0) = -\cos(0) = -1 $

Therefore, the magnetic flux density vector at the origin is:

$ \vec{B}_{origin} = 1 \vec{a_x} - 1 \vec{a_y} - 1 \vec{a_z} $

Calculating the Magnitude of $\vec{B}$

The magnitude of the magnetic flux density vector $\vec{B}$ is calculated using the formula:

$ |\vec{B}| = \sqrt{B_x^2 + B_y^2 + B_z^2} $

Substituting the components at the origin:

$ |\vec{B}_{origin}| = \sqrt{(1)^2 + (-1)^2 + (-1)^2} $

$ |\vec{B}_{origin}| = \sqrt{1 + 1 + 1} $

$ |\vec{B}_{origin}| = \sqrt{3} \, \text{Wb/m}^2 $

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Important Questions from Microprocessors

  1. What is the value in AL and CF after the following instruction in 8086 is executed?
    MOV AL, 8EH
    MOV CL, 02H
    SAR AL, CL
  2. What is the content in R1, after the following instructions are executed?
    CLR C
    MOV A,#4CH
    SUBB A,#6EH
    JNC NEXT
    CPL A
    INC A
    NEXT: MOV R1, A
  3. When TMOD is 10 H, the timer will operate as ____________.
  4. The Assembler directive in 8086 which is used to tell the assembler that the names or labels following the directive are in some other assembly module is, ____________.
  5. The location of flags in 8086 flag register in ascending order is
    A. CY
    B. T
    C. D
    D. Z
    E. O
    Choose the correct answer from the options given below:

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