The problem asks for the fraction of pizza left after two people eat portions sequentially.
Krishna eats $\\frac{1}{3}$ of the whole pizza. The fraction of pizza remaining after Krishna eats is:
$ 1 - \frac{1}{3} = \frac{3}{3} - \frac{1}{3} = \frac{2}{3} $
So, $\\frac{2}{3}$ of the pizza remains.
Devshya eats $\\frac{2}{5}$ of the *remaining* pizza. The remaining pizza is $\\frac{2}{3}$. The fraction Devshya eats is:
$ \frac{2}{5} \times \frac{2}{3} = \frac{2 \times 2}{5 \times 3} = \frac{4}{15} $
Devshya eats $\\frac{4}{15}$ of the original pizza.
To find the fraction of pizza left uneaten, subtract the portion Devshya ate from the portion remaining after Krishna ate:
$ \frac{2}{3} - \frac{4}{15} $
To subtract these fractions, find a common denominator, which is 15:
$ \frac{2}{3} = \frac{2 \times 5}{3 \times 5} = \frac{10}{15} $
Now, perform the subtraction:
$ \frac{10}{15} - \frac{4}{15} = \frac{10 - 4}{15} = \frac{6}{15} $
The fraction $\\frac{6}{15}$ can be simplified by dividing both the numerator and the denominator by their greatest common divisor, which is 3:
$ \frac{6 \div 3}{15 \div 3} = \frac{2}{5} $
Therefore, the fraction of the pizza left uneaten is $\\frac{2}{5}$.
Which fraction among the following is the least ?
\(\frac{5}{11}, \frac{7}{12}, \frac{8}{13}, \frac{9}{17}\)
Find the value of the following expression:
\(\frac{{3 \div 1 \times 2 + 5 - 2}}{{3 \times 3 - 2}}\)
Simplify the expression 441 ÷ \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)
If the sum of two positive numbers is 65 and the square root of their product is 26, then the sum of their reciprocals is:
The value of \(9 \div [\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{6}\div(\frac{3}{4}-\frac{1}{3})\;of\;\frac{2}{9}]\) is: